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ElenaW [278]
2 years ago
14

PLEASE HELP!!!!! x^2 + 12xy + 35y^2

Mathematics
2 answers:
SVEN [57.7K]2 years ago
7 0
The answer is = (x + 5y) (x + 7y)

Break the expression into two groups.
 
x^2 + 12xy + 35y^2
(x^2 + 5xy) (7xy + 35^2)

Factor out x from x^2 + 5xy: x(x + 5y)
Factor out 7y from 7xy + 35y^2: 7y(x + 5y)
=x(x + 5y) + 7y(x + 5y)

Next, factor out the common term (x+ 5y).

Answer = (x + 5y) (x + 7y)
ale4655 [162]2 years ago
4 0
By grouping, the answer is (x+5y)(x+7y) 
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What is an important requirement for an emergency fund? A. liquidity B. keeping it in a locked safe C. investing it in retiremen
polet [3.4K]

Answer:

<u>Hi there your correct answer to this is D. a high interest rate.</u>

Hope it helps! ;>

7 0
3 years ago
Read 2 more answers
If five numbers are selected at random from the set {1,2,3,...,20}, what is the probability that their minimum is larger than 5?
Zanzabum

Answer:

the probability that their minimum is larger than 5 is 0.2373

Step-by-step explanation:

For calculate the probability we need to make a división between the total ways to selected the 5 numbers and the ways to select the five numbers in which every number is larger than 5.

So the number of possibilities to select 5 numbers from 20 is:

<u>20                </u> * <u>      20         </u>*  <u>        20     </u> *<u>        20         </u>* <u>       20 </u>

First number  2nd number   3rd number  4th number   5th number

Taking into account that a number can be chosen more than once, and the order in which you select the numbers matters, for every position we have 20 options so, there are  20^{5} ways to select 5 numbers.

Then the number of possibilities in which their minimum number is larger than 5 is calculate as:

<u>15                </u> * <u>      15         </u>*  <u>           15     </u> *<u>        15          </u>* <u>       15 </u>

First number  2nd number   3rd number  4th number   5th number

This time for every option we can choose number from 6 to 20, so we have 15 numbers for every option and the total ways that satisfy the condition are  15^{5}

So the probability P can be calculate as:

P=\frac{15^{5} }{20^{5} } \\P=0.2373

Then the probability that their minimum is larger than 5 is 0.2373

7 0
3 years ago
(Geometry HELP) The perimeter of WXY is ___ cm?
jeka57 [31]
I hope this helps you



QR=WS=2.93



RS=QW =2.04


QS=XR =2.28


RS=XQ=2.04



SY=QR =2.93


RY=QS =2.28


XY=XR+RY=2.28+2.28=4.56


XW=XQ+QW=2.04+2.04=4.08


WY=WS+SY=2.93+2.93=5.86


Perimeter of XYW=XW+WY+XY


Perimeter of XYW=4.08+5.86+4.56


Perimeter of XYW =14.5


8 0
3 years ago
Helpppppp!!!!!!!!!!!!!
kupik [55]

28

The outlier would be 28 because it is much lower than the rest of the numbers in the group and removing it would make the mean increase.

3 0
2 years ago
Divide. If the polynomial does not divide evenly, include the remainder as a fraction.
Nostrana [21]

Answer:

-1 with a remainder of 9

7 0
2 years ago
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