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2 years ago

Find the value of x this is geometry

Mathematics

1 answer:

kvasek [131]2 years ago

4 0

Answer:

3 i think

Step-by-step explanation:

looked in photomath

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Chelsea made monthly payments for four years before her $13,440 loan was paid off. The loan had an interest rate of 5.86%, compo

lana [24]

Given:
PV = 13,440
i = 5.86% , compounded monthly
t = 4 years

13,440(0.0586/12))/(1-(1+0.0586/12)^-48= 15,109.44
15,109.44 + 156.60 = 15,266.04
15,266.04 - 13,440.00 = 1,826.04
<span>1,826.04/15,266.04 = 11.96 % Percentage total of Finance Charge of the total loa</span>

6 0

3 years ago

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Find an equation of the circle whose diameter has endpoints (1,-4) and (-3,6).

MAVERICK [17]

Answer:

$(x+1)^2+(y-1)^2=58$

Step-by-step explanation:

To find the equation of this circle, we must know the center and the radius.

We can find the radius by dividing the value of the distance formula by 2 (since $r=\frac{d}{2}$ ):

$d=\sqrt{(-3-1)^2+(6-(-4))^2}=\sqrt{116}\\r=d/2=\frac{\sqrt{116}}{2}$

We can then find the center of the circle by averaging the coordinates:

$\frac{1+(-3)}{2}=-1$

$\frac{-4+6}{2}=1$

Then, we substitute these values into the equation of a circle:

$(x-(-1))^2+(y-1)^2=(\frac{\sqrt{116}}{2})^2\\(x+1)^2+(y-1)^2=58$

3 0

3 years ago

A plane flies from Houston to New York City in 4 hours the distance I traveled was 1627 miles what is the average speed of the p

Nikolay [14]

1627 / 4 = 406.75 miles per hr

5 0

3 years ago

PICKING BRAINIEST<br> which equation could be used to solve for the length of XY?

liq [111]

The answer is in my attachment

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2 years ago

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What is the equation in point slope form of the line that is parallel to the given line and passes through the point (4,1)?

vovikov84 [41]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

$y-1=\stackrel{\stackrel{m}{\downarrow }}{2}(x-4)\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}$

so we're really looking for the equation of a line with a slope of 2 and that it passes through (4 , 1)

$(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\hspace{10em} \stackrel{slope}{m} ~=~ 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{2}(x-\stackrel{x_1}{4})$

kinda twins.

8 0

1 year ago