Answer:
Explanation:
Here, cell C-2 needs to express GFP and therefore, GAL4 should be functional in cell C-2. This can be achieved by expressing GAL4 in Regulatory DNA construct 3, and expressing GAL80, an inhibitor of GAL4 in Regulatory constructs 1 and 2. This arrangement expresses GAL4 in columns A and C, and inhibits GAL4 due to GAL80 expression in Columns A and B; and in rows 1 and 3.
Therefore, the only cell that expresses GAL4 is cell C-2.
The arrangement is:
1. Construct 1 should express GAL80
2. Construct 2 should express GAL80
3. Construct 3 should express GAL4
4. Construct 4 should not be used
Answer:
FfPp
Explanation:
If we take the two traits to be separate alleles, we can make flowers F (F is dominant; f is recessive) and pollen as P (P is dominant; p is recessive). So a pea plant with white flowers (recessive) and long pollen (dominant) will have the genotype ffPp or ffPP (because one dominant allele will express a dominant phenotype).
For this question, we will assume that the wild type (red flowers and long pollen) is homozygous, meaning it contains two dominant alleles.
If the wild type (FFPP) is crossed with the plant with white flowers and short pollen (ffpp), we can make a table illustrating the crosses. However, because there is only one possible gamete that each parent can form (FP and fp), we can assume that the F1 progeny will have identical genotypes, which can be expressed as FfPp (because combining the gamete from the wild type and the other parent can only give one phenotype).
I believe the thyroid controls most, if not all of those things. (Again, I'm not entirely sure.)
Answer:
C. 22
Explanation:
I just studied this last week
