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aleksandrvk [35]
3 years ago
8

I need help with this geometry

Mathematics
1 answer:
Naily [24]3 years ago
4 0

Answer:

ur choice answer is correct

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How many real solutions does this system of equations have? x2+y2=363x−y+1=0 A. 0 B. 3 C. 2 D. 1
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Answer:

Correct option: C -> 2

Step-by-step explanation:

The first equation is:

x^2+y^2=363

And the second equation is:

x-y+1=0

From the second equation, we have:

y = x + 1

Using this value of y in the first equation, we have:

x^2 + (x+1)^2 = 363

x^2 + x^2 + 2x + 1 = 363

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Calculating the discriminant Delta, we have:

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We have \Delta > 0, so we have two real values for x, therefore we have two solutions for this system.

Correct option: C.

(If the system of equation is actually:

x^2+y^2=36

3x-y+1=0

We would have:

y = 3x + 1

x^2+(3x+1)^2=36

x^2+9x^2+6x+1=36

10x^2+6x-35=0

\Delta = 36 + 1400 = 1436

We also have \Delta > 0, so we have two solutions for this system.

Correct option: C.)

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3 years ago
Consider a situation in which P(X) = 4/5 and P(Y) = 1/4. If P(X and Y) is = 1/5, which best describes the events?
kirill [66]
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Let the additional watts be x

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3 years ago
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