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lys-0071 [83]
3 years ago
13

There are 5 roads from Allen to baker, 7 roads from baker to Carlson, and 4 roads from Carlson to dodge. How many different rout

es from Allen to dodge by way of baker and Carlson are possible?
Mathematics
2 answers:
Basile [38]3 years ago
6 0

Answer:

140 routes

Total Number of roads from allen to dodge through baker and Carlson is 140 routes.

Step-by-step explanation:

Given;

Number of roads from Allen to baker = 5

Number of roads from baker to Carlson = 7

Number of roads from Carlson to dodge = 4

Total Number of routes from allen to dodge through baker and Carlson is;

N = 5×7×4

N = 140 routes

Lapatulllka [165]3 years ago
3 0

Answer:

140 different routes

Step-by-step explanation:

The first path (Allan to Baker) has 5 different options, so there are 5 possibilities. After that, there are 7 possibilities from Baker to Carlson. Then, there are 4 possibilities from Carlson to Dodge. To find the total number of possibilities, we just need to multiply the number of possibilities of each track, so:

5 * 7 * 4 = 140 possibilities, that is, 140 different routes.

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Step-by-step explanation:

Given - In selecting a sulfur concrete for roadway construction in regions that experience heavy frost, it is important that the chosen concrete has a low value of thermal conductivity in order to minimize subsequent damage due to changing temperatures. Suppose two types of concrete, a graded aggregate and a no-fines aggregate, are being considered for a certain road. The table below summarizes data on thermal conductivity from an experiment carried out to compare the two types of concrete.

Type            ni                xi                  si

Graded       42           0.486            0.187

No-fines      42           0.359           0.158

To find - a. Formulate the above in terms of a hypothesis testing problem.

b. Give the test statistic and its reference distribution (under the null hypothesis).

c. Report the p-value of the test statistic and use it to assess the evidence that this sample provides on the scientific question of difference in mean conductivity of the two materials at the 5% level of significance.

Proof -

a.)

Hypothesis testing problem :

H0 : There is significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.

H1 : There is no significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.

b)

Test statistic :

Z = \frac{x_{1} - x_{2} }{\sqrt{\frac{s_{1} ^{2} }{n_{1}}  + \frac{s_{2}^{2} }{n_{2}} } }

Z = \frac{0.486 - 0.359 }{\sqrt{\frac{0.03496 }{42}  + \frac{0.02496 }{42} } }

Z = \frac{0.127 }{\sqrt{0.001468}}

Z = \frac{0.127 }{0.0377}

⇒Z(cal) = 3.3687

Z(tab) = 1.96

As Z (cal) > Z(tab)

So, we reject H0 at 5% Level of significance

p-value = 0.99962

Hence

There is significant difference in mean conductivity at the two materials.

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3 years ago
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12x²-8x-15 should be your answer

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3 years ago
(2*1) +(6*1/1,000) write in standard form
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harkovskaia [24]

Answer:

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Step-by-step explanation:

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3 years ago
In 2012 your car was worth $10,000. In 2014 your car was worth $8,850. Suppose the value of your car decreased at a constant rat
monitta

Answer:

The function to determine the value of your car (in dollars) in terms of the number of years t since 2012 is:

f(t) = 10000(0.9407)^t

Step-by-step explanation:

Value of the car:

Constant rate of change, so the value of the car in t years after 2012 is given by:

f(t) = f(0)(1-r)^t

In which f(0) is the initial value and r is the decay rate, as a decimal.

In 2012 your car was worth $10,000.

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f(t) = 10000(1-r)^t

8850 = 10000(1-r)^2

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Thus

f(t) = 10000(1-r)^t

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