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2 years ago

What is the slope of the line that passes through the points (1,1) and (9,7)?

Mathematics

2 answers:

balu736 [363]2 years ago

5 0

Answer:

slope = $\frac{3}{4}$

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (1, 1) and (x₂, y₂ ) = (9, 7)

m = $\frac{7-1}{9-1}$ = $\frac{6}{8}$ = $\frac{3}{4}$

aalyn [17]2 years ago

3 0

It's 3/4, simple enough just do delta y over delta x

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Is 5.8 greater then fifty eight hundreths

Korolek [52]

Answer:

Step-by-step explanation:

fifty eight hundreths= 5,800

5.8<5,800

3 0

2 years ago

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Find the coordinates of the midpoints of the segment whose endpoints are H(4,8) and K (10,10)

creativ13 [48]

Answer:

(7,9)

Step-by-step explanation:

Use the midpoint formula to find the midpoint of the line segment.

4 0

2 years ago

I need help please. Thanks

Agata [3.3K]

Given:

m∠APD = (7x + 1)°

m∠DPC = 90°

m∠CPB = (9x - 7)°

To find:

The measure of arc ACD.

Solution:

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠APD + m∠DPC + m∠CPB = 180°

7x° + 1° + 90° + 9x° - 7° = 180°

16x° + 84° = 180°

Subtract 84° from both sides.

16x° + 84° - 84° = 180° - 84°

16x° = 96°

Divide by 16° on both sides.

x = 6

m∠APB = 180°

m∠BPD = (9x - 7)° + 90°

= (9(6) - 7)° + 90°

= 47° + 90°

m∠BPD = 137°

m∠APD = m∠APB + m∠BPD

= 180° + 137°

= 317°

<em>The measure of the central angle is congruent to the measure of the intercepted arc.</em>

m(ar ACD) = m∠APD

m(ar ACD) = 317°

The arc measure of ACD is 317°.

8 0

3 years ago

Which pairs of variables have a linear relationship? Select

Neko [114]

Answer:

Side length and perimeter of 1 face

Area of 1 face and surface area

Step-by-step explanation:

Suppose you are given cube with side length of x units.

Then

Side length = x units

Perimeter = 4x units

Area of 1 face $=x^2$ square units

Surface area $=6x^2$ square units

Volume $=x^3$ cubic units

A linear relationship is any equation that, when graphed, gives you a straight line.

Consider all options:

A. Side length and perimeter of 1 face is a linear relationship, because the graph of the function $y=kx$ is a straight line.

B. Perimeter of 1 face and area of 1 face is not a linear relationship, because the graph of this relationship is a quadratic parabola with equation $y=kx^2$ .

C. Surface area and volume is not a linear relationship, because the graph of this relationship is a curve with equation $y=kx^{\frac{3}{2}}$ .

D. Area of 1 face and surface area is a linear relationship, because the graph of the function $y=kx$ is a straight line.

E. Side length and volume is not a linear relationship, because the graph of this relationship is a cubic parabola with equation $y=kx^3$ .

6 0

3 years ago

Read 2 more answers

a projectile is thrown upward so that it's distance above the ground after T seconds is H equals -16t^2 + 672 T. After how many

Arada [10]

Step-by-step explanation:

T = time in seconds

H = distance

Tground = time to return to ground

Tmax = time at maximum height

H = -16T^2 + 672T...eqn 1

projectile returns to ground at H =0,

subs for H in eqn 1...

0 = -16T^2 + 672T

solving for T we get...

16T^2 = 672T

=> Tground = 42secs

Tmax = 0.5 Tground = 21secs

4 0

2 years ago