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Eddi Din [679]
3 years ago
12

Find the rule. solve for n

Mathematics
1 answer:
max2010maxim [7]3 years ago
5 0

Find the difference between the X and Y values goven:

10 - 1 = 9

12 - 3 = 9

15 - 6 = 9

The difference is 9, so the rule is subtracting 9 from the x value:

y = x -9

Now find Y when x is 20:

y = 20-9

y = 11

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Read 2 more answers
he​ half-life for a link on a social network website is 2.6 hours. Write an exponential function T that gives the percentage of
pychu [463]

Answer:

% Remaining= [1-(1/2)^{\frac{t}{2.6}}]x100

And replacing the value t =5.5 hours we got:

% Remaining= [1-(1/2)^{\frac{5.5}{2.6}}]x100 =76.922\%

Step-by-step explanation:

Previous concepts

The half-life is defined "as the amount of time it takes a given quantity to decrease to half of its initial value. The term is most commonly used in relation to atoms undergoing radioactive decay, but can be used to describe other types of decay, whether exponential or not".

Solution to the problem

The half life model is given by the following expression:

A(t) = A_o (1/2)^{\frac{t}{h}}

Where A(t) represent the amount after t hours.

A_o represent the initial amount

t the number of hours

h=2.6 hours the half life

And we want to estimate the % after 5.5 hours. On this case we can begin finding the amount after 5.5 hours like this:

A(5.5) = A_o (1/2)^{\frac{5.5}{2.6}}

Now in order to find the percentage relative to the initial amount w can use the definition of relative change like this:

% Remaining = \frac{|A_o - A_o(1/2)^{\frac{5.5}{2.6}}|}{A_o} x100

We can take common factor A_o and we got:

% Remaining= [1-(1/2)^{\frac{t}{2.6}}]x100

And replacing the value t =5.5 hours we got:

% Remaining = [1-(1/2)^{\frac{5.5}{2.6}}]x100 =76.922\%

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4 years ago
Kevin is observing the population of the fish he put into a pond. He built a pond and populated it with 500 fish. The population
laila [671]

Here we will use exponential form, which is

y = y_{0} e^{kt}

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Required equation is

y=500e^{x ln2} \\ y= 500 (2)^x

6 0
4 years ago
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