Answer:
The quantity of water drain after x min is 50 
Step-by-step explanation:
Given as :
Total capacity of rain barrel = 50 gallon
The rate of drain = 10 gallon per minutes
Let The quantity of water drain after x min = y
Now, according to question
The quantity of water drain after x min = Initial quantity of water × 
I.e The quantity of water drain after x min = 50 gallon × 
or, The quantity of water drain after x min = 50 gallon ×
Hence the quantity of water drain after x min is 50 Answer
C(x) = 1200(40) + 100
or
= mx+c
where m = 1200, x = 40, y = 100
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Step-by-step explanation:
x'=53
σ=16
n=144
a) hypothesis
H0:µ=55
Ha:µ<55
This is a left tailed test
b) Test statistics
- z=(x'-u)/(sigma/sqrt {n})
=(53-55)/(16/sqrt{144})
=-1.5
c)Pvalue at z=|-1.5|
pvalue= p(z>1.5)
=1-0.933193
=0.066807
=0.0668
<u>Decision</u>
since pvalue>alpha(0.05) fail to reject the null hypotheis.
<u>Conclusion</u>
There is not sufficient evidence to support the claim the new computer program has not reduce the time to retrieve the data.
d)since Pvalue>alpha(0.025),so fail to reject the null hypothesis.
No, change in conclusion.
