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3 years ago

A book is on sale for $6 off of the regular $24 price. What percent is the discount?

Mathematics

2 answers:

Vika [28.1K]3 years ago

8 0

6/24* 100= 25%. You multiply top ( 6 and 100) and divide to bottom (600 and 24) to get 25%.

Reika [66]3 years ago

5 0

$6 is 25% or 1/4.

I hope that helped! c:

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How to solve 4k-1.5k=50

padilas [110]

Combine like terms-- you can combine the k's:
$4k-1.5k=2.5k$

Now you have:
$2.5k=50$

Simply divide both sides by 2.5 to find the value of k:
$\frac{2.5k}{2.5}=\frac{50}{2.5}\\\\k=20$

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

when you go to answer this, can someone please give me the steps on how to do it, because I think I'm doing it wrong

leva [86]

Answer:

TUA=123

Step-by-step explanation:

so first we find <TUS in terms of x

so 180-11x-2

178-11x

so now we can use the sum of a triangle's angles which is always 180 to find the angles in triangle TUS

178-11x+5x+10+58=180

178-6x=112

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6 0

3 years ago

Quadrilateral ABCD is inscribed in this circle.

Lelechka [254]

Answer:

m∠C = 122°

Step-by-step explanation:

Opposite angles of a quadrilateral inscribed in a circle are supplementary. This means

m∠A + m∠C = 180°

m∠B + m∠D = 180°

To find angle C we need to find x, then subtract m∠A from 180°

x+20=3x

20=2x

x=10

Now we substitute 10 in for x

m∠A=2(10)+38

m∠A=20+38

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Now we subtract this value from 180.

m∠C=180-58

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4 0

3 years ago

The annual energy consumption of the town where Camilla lives in creases at a rate that is onal at any time to the energy consum

boyakko [2]

Answer:

6.575 trillion BTUs

Step-by-step explanation:

Let represent the annual energy consumption of the town as E

The rate of annual energy consumption * energy consumption at time past

dE/dt * E

dE/dt =K

k = the proportionality constant

c= the integration constant

(dE/dt=) kdt

lnE = kt + c

E(t) = e^kt+c ⇒ e^c e^kt e^c is a constant, and e^c = E₀

E(t) = E₀ e^kt

The initial consumption of energy is E(0)=4.4TBTU

set t = 0 then

4.4 = E₀ e⇒ E₀ (1)

E₀ = 4.4

E (t) = 4.4e^kt

The consumption after 5 years is t = 5, e(5) = 5.5TBTU

so,

E(5) = 5.5 = 4.4e^k(5)

e^5k = 5/4

We now take the log 5kln = ln(5/4)

5k(1) = ln(5/4)

k = 1/5 ln(5/4) = 0.04463

We find the town's annual energy consumption, after 9 years

we set t=9

E(9) = 4.4e^0.04463(9)

= 4.4(1.494301) = 6.5749TBTUs

Therefore the annual energy consumption of the town after 9 years is

= 6.575 trillion BTUs

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3 years ago