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2 years ago

Can someone plz help me with this i need it fast

Mathematics

1 answer:

liq [111]2 years ago

5 0

Answer:

$c^{2}+6\\ 4^{2} =16\\16+6= 22$

Step-by-step explanation:

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The points in the table lie on a line. Find the slope of the line.

wolverine [178]

Answer

Y=5x+2

I’m not sure but I think that’s the answer

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3 years ago

Uhh i need help please...

marishachu [46]

With what? what’s the question

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2 years ago

Read 2 more answers

Find the value of x in the triangle shown below.

otez555 [7]

Answer:

Thus, the value of x in the given triangle is 55°

Step-by-step explanation:

Given - Dimensions of triangle and angles

of triangle

Find - Value of x

Solution - The value of x in the given triangle is 55°.

As per the given dimensions of the triangle, the triangle is isosceles. This states that the neighbouring angle will be x° as well.

Thus, the mathematical expression of all the angles of a given triangle will be -

x + x + 80 = 190

2x + 80 = 190

2x = 190 - 80

2x = 110

x = 110/2

x = 55°

3 0

2 years ago

Health insurers are beginning to offer telemedicine services online that replace the common office visit. A company provides a v

Veronika [31]

Answer:

$\text {CI} = (60.54, \: 81.46)\\\\$

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

Step-by-step explanation:

Let us find out the mean savings for a televisit to the doctor from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

$\bar{x} = \$71$

Let us find out the standard deviation of savings for a televisit to the doctor from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

$s = \$ 22.35$

The confidence interval is given by

$\text {confidence interval} = \bar{x} \pm MoE\\\\$

Where the margin of error is given by

$$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\$

Where n is the sample of 20 online doctor visits, s is the sample standard deviation and $t_{\alpha/2}$ is the t-score corresponding to a 95% confidence level.

The t-score is given by is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 20 - 1 = 19

From the t-table at α = 0.025 and DoF = 19

t-score = 2.093

So, the margin of error is

$MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 2.093\cdot \frac{22.35}{\sqrt{20} } \\\\MoE = 2.093\cdot 4.997\\\\MoE = 10.46\\\\$

So the required 95% confidence interval is

$\text {CI} = \bar{x} \pm MoE\\\\\text {CI} = 71 \pm 10.46\\\\\text {CI} = 71 - 10.46, \: 71 + 10.46\\\\\text {CI} = (60.54, \: 81.46)\\\\$

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

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3 years ago

I HATE when people answer the question and think its right but its not and give themselves 5 star but its wrong and take my poin

Nana76 [90]

Answer:

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Step-by-step explanation:

1) don't do it

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3 years ago