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tatuchka [14]
3 years ago
5

2. The following formula relates three quantities: Force (F), mass (m), and acceleration (a).

Mathematics
2 answers:
masha68 [24]3 years ago
6 0

Answer:

Step-by-step explanation:

(a) Since we have F  = ma and we have to solve for a

                     there is multiplication between m and a and in order to solve for a ,we need to apply opposite operation of  multiplication ,therefore dividing both sides by m ,we get \frac{F}{m}=a

(b)  Let F be the force and m = 10 units is mass

        acceleration =  \frac{force}{mass} [ If we have given value of F then we divide the value of F by 10 to get acceleration  value.

                               = \frac{F}{10}

(c)   Mass m  will be  given by equation

            m=\frac{F}{a} =\frac{25}{5} =5 units

yKpoI14uk [10]3 years ago
4 0
A) f=ma

a=f/m

b) are You sure you typed it correct?

c) f=ma

25=m(5)
m=25/5
m=5
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4 years ago
Use Algorithm 7 to schedule the largest number of talks in a lecture hall from a proposed set of talks, if the starting and endi
3241004551 [841]

Answer:

If we arrange the talks from the lowest starting time to the highest ending time we get total of 11 talks.

using algorithm 7 we get answer   (1) - (3) - (6) - (9)   the largest number of talks scheduled.

Step-by-step explanation:

arranging the talks from lowest starting time to the highest ending time.

thus,

  1. 9:00 a.m. and 9:45 a.m.
  2. 9:30 a.m. and 10:00 a.m.
  3. 9:50 a.m. and 10:15 a.m.
  4. 10:00 a.m. and 10:30 a.m.
  5. 10:10 a.m. and 10:25 a.m.
  6. 10:30 a.m. and 10:55 a.m.
  7. 10:15 a.m. and 10:45 a.m.
  8. 10:30 a.m. and 11:00 a.m.
  9. 10:45 a.m. and 11:30 a.m.
  10. 10:55 a.m. and 11:25 a.m.
  11. 11:00 a.m. and 11:15 a.m.

we start from the earliest time as

9:00 a.m. and 9:45 a.m which is (1).

After the talk is finished we pick the nearest time for another talk which starts at

9:50 a.m. and 10:15 a.m which is (3).

After this talk we again pick the nearest time for another talk which becomes

10:30 a.m. and 10:55 a.m which is (6).

and lastly

10:45 a.m. and 11:30 a.m which is (9).

Note: we didn't choose other times because we cannot talk at 2 or 3 places at the same time. so we pick another when one talk is finished.

thus the answer is (1) - (3) - (6) - (9) as the largest number of talks scheduled.

4 0
4 years ago
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Romashka [77]
There’s literally no actual question so how could we help?
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3 years ago
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