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2 years ago

9

Suppose the function ℎ() represents the height of a ball, in meters, t seconds after being thrown. Which expression represents t

he change in the height between 1 and 3 seconds?
Group of answer choices

ℎ(3)−ℎ(1)

ℎ(3)

ℎ(1)

12(ℎ(1)−ℎ(3))

1 answer:

Tasya [4]2 years ago

7 0

The first option is the answer pls mark as brainless

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Suppose I have an urn with 9 balls: 4 green, 3 yellow and 2 white ones. I draw a ball from the urn repeatedly with replacement.

Mrrafil [7]

Answer:

$E(X_n)=\frac{2(n-1)}{27}$

$E(y)=\frac{14}{9}$

Step-by-step explanation:

From the question we are told that:

Sample size n=9

Number of Green $g=4$

Number of yellow $y=4$

Number of white $w=4$

Probability of Green Followed by yellow P(GY) ball

$P(GY)=\frac{4}{9}*\frac{3}{9}$

$P(GY)=\frac{4}{27}$

Generally the equations for when n is even is mathematically given by

$Probability of success P(S)=\frac{4}{27}$

$Probability of Failure P(F)=\frac{27-4}{27}$

$Probability of Failure P(F)=\frac{23}{27}$

Therefore

$E(X_n)=\frac{n}{2}*P$

$E(X_n)=\frac{n}{2}*\frac{4}{27}$

$E(X_n)=\frac{2n}{27}$

Generally the equations for when n is odd is mathematically given by

$\frac{n-1}{2}$

$E(X_n)=\frac{n-1}{2}*\frac{4}{27}$

$E(X_n)=\frac{2(n-1)}{27}$

b)

Probability of drawing white ball

$P(w)=\frac{2}{9}$

Therefore

$E(w)=\frac{1}{p}$

$E(w)=\frac{1}{\frac{2}{9}}$

$E(w)=\frac{9}{2}$

Therefore

$E(y)=[E(w)-1]\frac{4}{9}$

$E(y)=[\frac{9}{2}-1]\frac{4}{9}$

$E(y)=\frac{14}{9}$

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3 years ago

Estimate the sum or difference 4/5+18/20 A 1 B 1 ,1/2 C 2

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Answer:

C 2

Step-by-step explanation:

4/5+18/20=1.7

Round that up it’s 2

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Which is bigger? 1.27 or 1 1/3?

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3 years ago

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erik [133]

30% are blueberry muffins.

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Use distributive property to remove the parentheses -5(-2v+3y-1)

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Answer:

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