Recall that variation of parameters is used to solve second-order ODEs of the form
<em>y''(t)</em> + <em>p(t)</em> <em>y'(t)</em> + <em>q(t)</em> <em>y(t)</em> = <em>f(t)</em>
so the first thing you need to do is divide both sides of your equation by <em>t</em> :
<em>y''</em> + (2<em>t</em> - 1)/<em>t</em> <em>y'</em> - 2/<em>t</em> <em>y</em> = 7<em>t</em>
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You're looking for a solution of the form

where


and <em>W</em> denotes the Wronskian determinant.
Compute the Wronskian:

Then


The general solution to the ODE is

which simplifies somewhat to

Answer:
<em>the third one answer choice</em>
Step-by-step explanation:
<u><em>⊕ Place the triangle on a coordinate grid such that vertex A is at the origin, and segment AC lies on the x-axis.</em></u>
You will be able to see the length of segment AC and length of segment DE, and also will be able to see if AC║DE.
12.4 / 6.2 = 2
so other side of enlarged rectangle = 1.8 x 2 = 3.6
Perimeter of enlarged rectangle = 2(3.6 + 12.4) = 32
Answer: 32 feet
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Another way to do:
12.4 / 6.2 = 2
SF = 2
The original rectangle has a perimeter of 16
Perimeter of the enlarged rectangle = 16 x 2 = 32
Answer: 32 feet
Answer:
man it’s one in the morning and your picture is blurry a f
Step-by-step explanation: