Answer:
C
Step-by-step explanation:
a is defined first as 5. So a = 5.
b is defined after the circle b = -2
a^2 = 5^2 = 25
B^4 =(- 2)^4 = 16
Therefore sqrt(a^2 * b^4) = sqrt(25 * 16) = sqrt(400) = 20
The answer is C
If you use a proportion, you'll get:

Then, you use cross products:

Then, you algebraically solve x:

The answer is 5/3 inches , or 1 5/13 inches, or 1.6 repeating.
Answer:
y = 10x + 7
Step-by-step explanation:
Answer:
0.28 meters per second.
Step-by-step explanation:
We have that the speed formula is as follows:
v = d / t
In this case they tell us that the distance is 2 km the equivalent of 2000 meters and the time is 2 hours the equivalent of 7200 seconds, we replace and we are left with:
v = 2000/7200 = 0.28
Therefore it ran 0.28 meters per second.
Answer:
Example:
A bag contains 3 black balls and 5 white balls. Paul picks a ball at random from the bag and replaces it back in the bag. He mixes the balls in the bag and then picks another ball at random from the bag.
a) Construct a probability tree of the problem.
b) Calculate the probability that Paul picks:
i) two black balls
ii) a black ball in his second draw
Solution:
tree diagram
a) Check that the probabilities in the last column add up to 1.
b) i) To find the probability of getting two black balls, first locate the B branch and then follow the second B branch. Since these are independent events we can multiply the probability of each branch.
ii) There are two outcomes where the second ball can be black.
Either (B, B) or (W, B)
From the probability tree diagram, we get:
P(second ball black)
= P(B, B) or P(W, B)
= P(B, B) + P(W, B)