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Deffense [45]
3 years ago
6

What does v= bh over 3 for b=2 inches squared and h=32 inches equal

Mathematics
1 answer:
ss7ja [257]3 years ago
6 0

V=bh/3

V=(2*32)/3

V=64/3

V=21.3333  ( Round answer as needed)

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Need help please on this one
OverLord2011 [107]

Answer:   3/2

==========================================================

Explanation:

Pick any two points on the red line. I'll pick (0,1) and (2,4)

Those coordinates will be plugged into the slope formula below

m = (y2 - y1)/(x2 - x1)

m = (4 - 1)/(2 - 0)

m = 3/2

This means we go up 3 and over to the right 2 when traveling along this red line.

8 0
3 years ago
ALMOST DONE!!!! HELP ME!!!!
Naddik [55]

4+√x=10 ← Subtract 4 from both sides

√x = 6 ← square both sides to get rid of the square root

x = 36 or B


5 0
4 years ago
The full answer I don't understand
Slav-nsk [51]
DOB
that is from 55 to 145

acute means angle is less than 90 degrees
right means equal to 90
obtuse means greater than 90

so

55 to 145
145-55=90
it is right angle
4 0
4 years ago
Circle C has a center at (-2,10) and contains the point P(10,5). Which equation represents circle C?
Rina8888 [55]

Answer:

The equation that represents circle C is (x+2)^2+(y-10)^2=169.

Step-by-step explanation:

A circle is the set of all points in the plane which maintains a fixed finite distance <em>r</em> from a fixed point <em>O = (a, b)</em>. Here <em>O</em> is called the center, and <em>r</em> is called the radius of that circle.

The standard equation for a circle with center (a, b) and radius <em>r</em> is

                                        (x-a)^2+(y-b)^2=r^2

We are told that the center of this circle is (-2, 10), so

                                        (x+2)^2+(y-10)^2=r^2

We are also told that the circle contains the point  (10, 5), so we will use that information to find the radius <em>r.</em>

<em />(10+2)^2+(5-10)^2=r^2\\\\r^2=\left(10+2\right)^2+\left(5-10\right)^2\\\\r^2=12^2+5^2\\\\r^2=144+25\\\\r^2=169\\\\r=\sqrt{169}=13<em />

Therefore, the equation that represents circle C is

(x+2)^2+(y-10)^2=13^2\\\\(x+2)^2+(y-10)^2=169

7 0
3 years ago
let (-5,-7) be a point on the terminal side of theta. find the exact values of cos theta, sec theta, and cot theta
Svet_ta [14]

a. The exact value of cosθ = -5/√74

b. The exact value of secθ = -√74/5

c. The exact value of cotθ = 5/7

<h3>How to find the trigonometric ratios</h3>

Since the terminal side of the θ is the point, (-5, -7), we need to find the length of the terminal side.

So, r = √(x² + y²) where

  • x = -5 and
  • y = -7

So, r = √(x² + y²)

r = √((-5)² + (-7)²)

r = √(25 + 49)

r = √74

<h3>The value of the trigonometric ratio cosθ</h3>

Since the trigonometric ratio cosθ = x/r

Substituting the values of x and r into the equation, we have

cosθ = x/r

cosθ = -5/√74

So, the exact value of cosθ = -5/√74

<h3>The value of the trigonometric ratio secθ</h3>

Since the trigonometric ratio, secθ = r/x

Substituting the values of x and r into the equation, we have

secθ = r/x

secθ = √74/-5

secθ = -√74/5

So,  the exact value of secθ = -√74/5

<h3>The value of the trigonometric ratio cotθ</h3>

Since the trigonometric ratio cotθ = x/y

Substituting the values of x and y into the equation, we have

cotθ = x/y

cotθ = -5/-7

cotθ = 5/7

So,  the exact value of cotθ = 5/7

Learn more about trigonometric ratios here:

brainly.com/question/1518222

#SPJ1

3 0
2 years ago
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