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laiz [17]
3 years ago
8

22. Suppose that the McAllister's purchased 15 plane tickets for an upcoming family trip to Paris. Each ticket independently has

a 0.01 probability of being accidentally thrown away. What is the probability that exactly one of the tickets is accidentally thrown away?

Mathematics
1 answer:
ANEK [815]3 years ago
3 0

Answer:

d

Step-by-step explanation:

The correct answer is (D). If X is the number of tickets thrown away, then this is a binomial setting with n = 15 and p = 0.01.

Then P(X = 1) = 15C1 (0.01)1(0.99)14 = 15(0.01)1(0.99)14.

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Given radical a and radical b are in simplest radical form and radical a timed radical b equals c radical d and c radical d is i
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Answer:

See below.

Step-by-step explanation:

Since sqrt(a) and sqrt(b) are in simplest radical form, that means a and b have no perfect square factors. When sqrt(a) and sqrt(b) are multiplied giving c * sqrt(d), the fact that c came out of the root means that there was c^2 inside the product sqrt(ab). This means that a and b have at least one common factor.

ab = c^2d

Example:

Let a = 6 and let b = 10.

sqrt(6) and sqrt(10) are in simplest radical form.

Now we multiply the radicals.

sqrt(a) * sqrt(b) = sqrt(6) * sqrt(10) = sqrt(60) = sqrt(4 * 15) = 2sqrt(15)

We have c = 2 and d = 15.

ab = c^2d

6 * 10 = 2^2 * 15

60 = 60

Our relationship between a, b and c, d works.

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