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1 year ago

identify the special product by writing the letter of the answer on the space provided ( question in photo number 1 )

Mathematics

1 answer:

Taya2010 [7]1 year ago

8 0

Question:

Solution:

Note that :

$x^2+9x\text{ + 20 = 1(x+4)(x+5)}$

where the left hand of the equation represents a trinomial and the right hand of the equation represents a product of two binomials. Then, we can conclude that the correct answer is:

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Plz I need help with I have 20 mins to submit it

Sedaia [141]

I think its not sure: 42.437m

6 0

3 years ago

180kg, 250kg, 200kg, 209kg, 195kg, 205kg, 190kg, 188kg, 192kg. What is the IQR of the lion's weights.

velikii [3]

Answer:

Step-by-step explanation:

Given the data:

180kg, 250kg, 200kg, 209kg, 195kg, 205kg, 190kg, 188kg, 192kg

The interquartile range (IQR) = Q3 - Q1

Reordering the data:

180, 188, 190, 192, 195, 200, 205, 209, 250

Q3 = 3/4(n+1)th term

Q3 = 3/4(10) = 7.5 th term = (205+209)/2 = 207

Q1 = 1/4(n+1)th term

Q1 = 1/4(10) = 2.5th term = (188+190)/2 = 189

Q3 - Q1 = 207 - 189 = 18

3 0

3 years ago

Suppose that you pick a bit string from the set of all bit strings of length ten. Find the probability that a) the bit string ha

emmasim [6.3K]

Answer:

45/1024
1/4
15/128
193/512
9/512

Step-by-step explanation:

There are 2^10 = 1024 bit strings of length 10.

a) There are 10C2 = 45 ways to have exactly two 1-bits in 10 bits

p(2 1-bits) = 45/1024

b) Of the four (4) possibilities for beginning and ending bits (00, 01, 11, 10), exactly one (1) of those is 00.

p(b0=0 & b9=0) = 1/4

c) There are 10C7 = 120 ways to have seven 1-bits in the bit string.

p(7 1-bits) = 120/1024 = 15/128

d) ∑10Ck {for k=0 to 4} = 386 is the total of the number of ways to have 0, 1, 2, 3, or 4 1-bits in the string. If there are more than that, there won't be more 0-bits than 1-bits

p(more 0 bits) = 386/1024 = 193/512

e) The string will have two 1-bits if it starts with 1 and there is a single 1-bit among the other 9 bits. There are 9 ways that can happen, among the 512 ways to have 9 remaining bits.

p(2 1-bits | first is a 1-bit) = 9/512

6 0

3 years ago

What does the quadratic function

nikklg [1K]

Answer:

f(x) = (x -3)^2 - 1

Step-by-step explanation:

f(x) = x^2 - 6x + 8

a = 1, b = -6 and c = 8

So we are finding half of the b equation (ignore the negative sign)

Half of 6 is 3, so we are going to square 3 (3^2 = 9) and add 9 to the left side and subtract 9 to the right side

(x) = (x^2 - 6x + 9) + (8 - 9)

You can tell the polynomial is a perfect square, so we will have to factor it using the perfect square method

(x^2 - 6x + 9)

square toot of x^2 is x and square root of 9 is 3 and the operation sign after the a number is a minus sign

(x -3)^2

Don't forget the rest of the equation from before

(x -3)^2 + (8 - 9)

(x -3)^2 - 1

So the equation is f(x) = (x -3)^2 - 1

6 0

3 years ago

can someone help me with this and give an explanation on how to do it? So i can know with the others.

MaRussiya [10]

Answer:

Values of y in order: 0, 2, 4, 6

Step-by-step explanation:

Hi there!

In the table, the first value of x is -2. To find the value of y for this row of the table, we can use the given equation $y=2x+4$ .

$y=2x+4$

Plug in -2 as the value of x

$y=2(-2)+4\\y=-4+4\\y=0$

Therefore, y is 0 when x is -2. (In the table, in the row where x is -2, y would be 0.)

We repeat this process for the rest of the values in the table.

When x=-1:

$y=2(-1)+4\\y=-2+4\\y=2$

When x=0:

$y=2(0)+4\\y=0+4\\y=4$

When x=1:

$y=2(1)+4\\y=2+4\\y=6$

I hope this helps!

6 0

3 years ago