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Mamont248 [21]
3 years ago
9

8+8b+2b = 2b+16 solve

Mathematics
1 answer:
Mamont248 [21]3 years ago
6 0
B=1....................
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4 to the power of 55
LenaWriter [7]

\\ \sf\longmapsto 4^{55}

\\ \sf\longmapsto (4^5)^{11}

\\ \sf\longmapsto 1024^{11}

\\ \sf\longmapsto 1024^31024^41024^3

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Virty [35]

Answer:

10th term of the sequence = 0.537

Step-by-step explanation:

First three terms of the sequence are → 5, 4, \frac{16}{5}..........

Ratio of 2nd and 1st term of the sequence = \frac{4}{5}

Ratio of 3rd and 2nd term of the sequence = \frac{\frac{16}{5} }{4}

                                                                        = \frac{4}{5}

Therefore, ratio between every successive term to the previous term is common.

Common ratio 'r' = \frac{4}{5}

First term of the sequence 'a' = 5

nth term of a geometric sequence = a(r)^n

Therefore, nth term of the given term will be  T_n=5(\frac{4}{5})^n

Now we have to find the 10 term of the given sequence.

For n = 10,

T_{10}=5(\frac{4}{5})^{10}

      = 0.53687

      ≈ 0.537

Therefore, 10th term of the sequence is 0.537

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