Answer:
1. Using the graph, describe the events that occur in the body during the first year of
HIV infection.
2. Describe what happens between the first year and the tenth year of infection.
3. Explain why the concentration of antibodies begins to decrease after nine years of
infection.
4. At what point on the graph does an infected person have AIDS?
5. Why does the number of HIV particles begin to level off after nine years?
6. How do you think the high rates of HIV transmission in humans might be related to the length of time it takes for the virus to develop into AIDS?
Answer:
The reaction rate of the digestion helps in understanding which part of the digestive system having trouble in digestion especialy stomach and intenstine related.
It involves the fact that most of the enrgy or calories are get by the small intestine and also vitamins and minerals are absorbed by this part of the digestive system so if the small intestine is having problem the rate of digestion would be affected and and an individual could be malabosrbed.
If the problem lies in the stomach it might show some effects of a poor digestion, however the rate of digestion would be better than if the problem lies in the small intestine.
Answer:
38 ATP
Explanation:
On complete oxidation of one molecule of glucose yields 38 ATP. Break up of energy production is given below:
- During glycolysis 2 ATP and 2 NADH is produced.
- During formation of Acetyl CoA, 2 NADH is produced.
- During Citric Acid Cycle, 2 ATP, 6 NADH, 2 FADH₂ are produced.
Finally during Electron transport chain, reduced coenzymes NADH and FADH₂ oxidised to release ATP. Each NADH produce 3ATP and each FADH₂ produces 2 ATP. Altogether 10 NADH is produced during entire process of cellular respiration which yield 30 ATP and 2 FADH₂ yields 4 ATP. Therefore, on complete oxidation of one molecule of glucose yields 38 ATP.
The <em>Hydra </em>offspring will also have 30 chromosome.
Explanation:
- Budding is a method of asexual reproduction.
- Asexual reproduction takes place through mitosis where diploid cells divide to give rise to identical cells with same chromosome number.
- Hydra reproduces through budding thus, if the parent hydra has 30 chromosome then the offspring will also have 30 chromosome.
<span>It has to be 100mL as total mass = 400g
Moles HCl = 0.05; moles Ba(OH)2 = 0.15
If volume HCl is 100mL then moles HCl = 0.05 and Ba(OH)2 is excess
If 2 moles HCl release 118 kJ then
0.05 moles HCl releases 2.95 kJ
q = cm deltaT
c=4.18 x 10-3 kJ/c.g
DeltaT = q/cm = 2.95/4.18 x 10-3 x 400 = 1.76 degrees rise so final temp = 1.76+ 25</span>
