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valentina_108 [34]
3 years ago
9

Use the given information to construct a 99% confidence interval estimate of the mean of the population. n = 39, σ = 3.86, Xbar

= 41.7
40.1 < μ < 43.3



40.5 < μ < 42.9



–9.4 < μ < 92.8



41.4 < μ < 42.0
Mathematics
1 answer:
horsena [70]3 years ago
4 0

Answer:

40.1 < μ < 43.3

Step-by-step explanation:

Margin of error = critical value × standard error

ME = CV × SE

At 99% confidence and 38 degrees of freedom, CV = 2.712.

SE = s / √n

SE = 3.86 / √39

SE = 0.618

So the margin of error is:

ME = 2.712 × 0.618

ME = 1.7

So the 99% confidence interval of the population mean is:

μ = 41.7 ± 1.7

40.0 < μ < 43.4

Closest answer is the first one.

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Could someone answer and explain these please? Thank you!
Oksana_A [137]

Answer 1:

It is given that the positive 2 digit number is 'x' with tens digit 't' and units digit 'u'.

So the two digit number x is expressed as,

x=(10 \times t)+(1 \times u)

x=10t+u

The two digit number 'y' is obtained by reversing the digits of x.

So, y=(10 \times u)+(1 \times t)

y=10u+t

Now, the value of x-y is expressed as:

x-y=(10t+u)-(10u+t)

x-y=10t+u-10u-t

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Answer 2:

It is given that the sum of infinite geometric series with first term 'a' and common ratio r<1 = \frac{a}{1-r}

Since, the sum of the given infinite geometric series = 200

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\frac{a}{1-0.15}=200

\frac{a}{0.85}=200

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a=170

The nth term of geometric series is given by ar^{n-1}.

So, second term of the series = ar^{2-1} = ar

Second term = 170 \times 0.15

= 25.5

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Step-by-step explanation:


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Answer:

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trapecia [35]
I would write the missing variable as x. It's what everyone uses.
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Answer:

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