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enyata [817]
3 years ago
9

PLZ HELP!!! Which graph represents the function?

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
6 0

All three of those graphs are functions.  

The main thing about a function is for every input in the domain there is exactly one output.  That doesn't mean that there has to be a y for every x;  the xs with no output, no y, are not in the domain of the function.

So to be a function for every x there needs to be <em>at most one </em>y.

The test for that is called the <em>vertical line test.</em>  If you can draw a vertical line (x=constant) through two points of the graph, that graph does not represent a function.

All three of these functions pass the vertical line test.  For the first the questionable point is x=-2.  A vertical line there passes through the graph at y=0.  It doesn't pass through the graph at y=-2 -- the open circle means that interval is open, it doesn't include (-2,-2).  So a vertical line passes through at most one point on the graph at all (shown) places, therefore it's a function.

The second one is similar at x=-2. At x=0 there's an open point; the function has no value there.  x=0 is not part of the domain.  That doesn't mean this isn't a function; it passes the vertical line test, so it's a function.

The third is like the second except now at x=-2 the value's in the right branch, y=-8.  Still this passes the vertical line test, so it's a function too.

Answer: all of the above

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Step-by-step explanation:

Assuming this question: "Calculate the range, population variance, and population standard deviation for the following data set. If necessary, round to one more decimal place than the largest number of decimal places given in the data. 2,3,4,5,6,7,8,9,10,11 "

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The range is defined as Range = Max -Min and if we replace we got:

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Now we can calculate the population mean with this formula:

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And if we replace we got:

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The population variance is given by:

\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}

And after replace we got: \sigma^2 =8.25 \approx 8.3

And the population standard deviation would be just the square root of the variance and we got:

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