1 Subtract <span><span>yy</span>y</span> from both sides
<span><span><span>43−y=<span>x3</span>−5</span>43-y=\frac{x}{3}-5</span><span>43−y=<span><span>3</span><span>x</span><span></span></span>−5</span></span>
2 Add <span><span>55</span>5</span> to both sides
<span><span><span>43−y+5=<span>x3</span></span>43-y+5=\frac{x}{3}</span><span>43−y+5=<span><span>3</span><span>x</span><span></span></span></span></span>
3 Simplify <span><span><span>43−y+5</span>43-y+5</span><span>43−y+5</span></span> to <span><span><span>48−y</span>48-y</span><span>48−y</span></span>
<span><span><span>48−y=<span>x3</span></span>48-y=\frac{x}{3}</span><span>48−y=<span><span>3</span><span>x</span><span></span></span></span></span>
4 Multiply both sides by <span><span>33</span>3</span>
<span><span><span>(48−y)×3=x</span>(48-y)\times 3=x</span><span>(48−y)×3=x</span></span>
5 Regroup terms
<span><span><span>3(48−y)=x</span>3(48-y)=x</span><span>3(48−y)=x</span></span>
6 Switch sides
<span><span><span>x=3(48−y)</span>x=3(48-y)</span><span>x=3(48−y<span>)</span></span></span>
Answer:
<h2>360 cakes</h2>
Step-by-step explanation:
<h2>soln:</h2><h2>onecake =240\8=30</h2><h2>then 12 cakes =30×12=360</h2>
D and B would be my guess.
T=3
l=Prt
105=700x0.05t <-substitute for the variables
105=35t <- multiply 700 and 0.05
3=t <- divde 35 on both sides