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Zigmanuir [339]
3 years ago
11

Out of 11 people surveyed at the mall, 2 have a car based on these results of the 429 people at the mall how many have a car

Mathematics
1 answer:
vladimir1956 [14]3 years ago
4 0

Answer:

78 people

Step-by-step explanation:

Given that out of 11 people surveyed at the mall, 2 have a car.

Based on these results if this ratio remains constant, then by unitary method

1 people surveyed at the mall, \frac{2}{11} people have a car.

Therefore, 429 people surveyed at the mall, \frac{2}{11} \times 429 = 78 people will have a car. ( Answer )

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63 × 510 = 32130

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3 0
3 years ago
When making a fruit salad, a chef chooses 7 fruits from 10 that are in season. how many different fruit salads can the chef crea
Furkat [3]
For this example, we must combine not permutate; this because a salad in which you first use apple then tomato is the same as the one in which you use first tomato then apple, so order does not matter.

Me must do "10 combine 7" which is written by the binomial coefficient (_{7} ^{10}); in general a binomial coefficient is written by:
(_{k} ^{n})= \frac{n!}{k!(n-k)!}

In which n and k are positive integers, such that n\ \textgreater \ k.

So, for this problem:
(_{7} ^{10})= \frac{10!}{7!(10-7)!}=\frac{10!}{7!3!}= \frac{10*9*8}{3*2}=10*3*4=120

Hence, there are 120 different ways to make the fruit salad.
5 0
3 years ago
How many elements are in the union of five sets if the sets contain 10,000 elements each, each pair of sets has 1000 common elem
masya89 [10]

Answer:

40951

Step-by-step explanation:

Using the principles of inclusion - Exclusion

Where C(n,r)=n!/(n-r)!r!

Total elements in the five sets including number repetition is given as (10000)×C(5, 1) =10000× 5!/(5-1)!1!=10000×5=50000

Total Number of elements in each pair including number repetition of sets is given as

=(1000) × C(5, 2) =10000

Number of elements in each triple of sets is given as

=(100) × C(5, 3) =1000

Number of elements in every four sets

=(10) × C(5, 4)=50

Number of elements in every one set

(1) × C(5, 5)=1

Therefore total number of unique elements=50000-10000+1000-50+1

=40951

5 0
3 years ago
Sebastian has $3.75 worth of dimes and quarters. He has a total of 21 dimes and quarters altogether. Determine the number of dim
Nostrana [21]

Answer:

Sebastian cold have 10 dimes and 11 quarters.

Step-by-step explanation:

11 quarters = $2.75

10 dimes = $1.00

6 0
3 years ago
Center: (-9, -3), point on circle: (-11, 2)
Vsevolod [243]

Answer:

y = -\frac{5}{2}x-\frac{51}{2}

Step-by-step explanation:

6 0
3 years ago
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