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3 years ago

Out of 11 people surveyed at the mall, 2 have a car based on these results of the 429 people at the mall how many have a car

Mathematics

1 answer:

vladimir1956 [14]3 years ago

4 0

Answer:

78 people

Step-by-step explanation:

Given that out of 11 people surveyed at the mall, 2 have a car.

Based on these results if this ratio remains constant, then by unitary method

1 people surveyed at the mall, $\frac{2}{11}$ people have a car.

Therefore, 429 people surveyed at the mall, $\frac{2}{11} \times 429 = 78$ people will have a car. ( Answer )

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Blood is a buffer solution. When carbon dioxide is absorbed into the bloodstream, it produces carbonic acid and lowers the pH. T

Irina18 [472]

Answer:

x ≅ 20.10 torr

Step-by-step explanation:

Given that the equation which models blood pH in the question is;

pH(x)=6.1+log(800/x)

where;

pH = 7.7

x = partial pressure of carbon dioxide in arterial blood, measured in torr.

we are asked to find (x)

In order to do that, we use the given equation:

pH(x)=6.1+log(800/x)

since pH = 7.7

7.7 = 6.1 + log (800/x)

7.7 - 6.1 = log (800/x)

1.6 = log (800/x)

$10^{1.6}= \frac{800}{x}$

$x= \frac{800}{10^{1.6}}$

x = 20.09509145

x ≅ 20.10 torr

4 0

3 years ago

Need a lil help please

Georgia [21]

Answer:

B(2, 4)

Step-by-step explanation:

Given points:

A(-1, -9) and M(0.5, -2.5)

Let the coordinates of B are (x, y)

Use midpoint formula to determine the point B:

0.5 = (- 1 + x)/2 ⇒ 1 = -1 + x ⇒ x = 1 + 1 = 2
-2.5 = (-9 + y)/2 ⇒ -5 = -9 + y ⇒ y = -5 + 9 = 4

3 0

3 years ago

2( 4x + 2) = 4x - 12(x-1)

aksik [14]

Answer:

$x=\frac{1}{2}$

Step-by-step explanation:

distribute 2 into (4x+2) and -12 into (x-1)

8x+4=4x-12x+12

combine like terms

8x+4=-8x+12

add -8x on both sides

8x+8x+4=12

16x+4=12

subtract 4 on both sides

16x=8

divide both sides by 16

x=1/2

hope this helps

8 0

3 years ago

Ahmad lost 50 dollars from his pocket. Write a signed number to represent this change.

IRINA_888 [86]

Answer:

-50

Step-by-step explanation:

it could be X-50=?

8 0

3 years ago

It is estimated that 75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell

Mademuasel [1]

Answer:

a) 75

b) 4.33

c) 0.75

d) $3.2 \times 10^{-13}$ probability that no one in a simple random sample of 100 young adults owns a landline

e) $6.2 \times 10^{-61}$ probability that everyone in a simple random sample of 100 young adults owns a landline.

f) Binomial, with $n = 100, p = 0.75$

g) $4.5 \times 10^{-8}$ probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they do not own a landline, or they do. The probability of an young adult not having a landline is independent of any other adult, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell phone at home.

This means that $p = 0.75$

(a) On average, how many young adults do not own a landline in a random sample of 100?

Sample of 100, so $n = 100$

$E(X) = np = 100(0.75) = 75$

(b) What is the standard deviation of probability of young adults who do not own a landline in a simple random sample of 100?

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100(0.75)(0.25)} = 4.33$

(c) What is the proportion of young adults who do not own a landline?

The estimation, of 75% = 0.75.

(d) What is the probability that no one in a simple random sample of 100 young adults owns a landline?

This is P(X = 100), that is, all do not own. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 100) = C_{100,100}.(0.75)^{100}.(0.25)^{0} = 3.2 \times 10^{-13}$

$3.2 \times 10^{-13}$ probability that no one in a simple random sample of 100 young adults owns a landline.

(e) What is the probability that everyone in a simple random sample of 100 young adults owns a landline?

This is P(X = 0), that is, all own. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{100,0}.(0.75)^{0}.(0.25)^{100} = 6.2 \times 10^{-61}$

$6.2 \times 10^{-61}$ probability that everyone in a simple random sample of 100 young adults owns a landline.

(f) What is the distribution of the number of young adults in a sample of 100 who do not own a landline?

Binomial, with $n = 100, p = 0.75$

(g) What is the probability that exactly half the young adults in a simple random sample of 100 do not own a landline?

This is P(X = 50). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 50) = C_{100,50}.(0.75)^{50}.(0.25)^{50} = 4.5 \times 10^{-8}$

$4.5 \times 10^{-8}$ probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

8 0

3 years ago