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Scrat [10]
3 years ago
13

Please help me with this math problem!!!

Mathematics
1 answer:
White raven [17]3 years ago
3 0

Answer:

B.

Step-by-step explanation:

slope = (y2-y1)/(x2-x1) = (1-17)/(14 - 18)

But she got (1-17)/(18-14). So B.

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Alex purchased a new car for $28,000. The car's value depreciates 7.25% each year. What will be the value of the car 5 years aft
Zanzabum
The value would be 28,000*(1-0.0725)*(1-0.0725)*(1-0.0725)*(1-0.0725)*(1-0.0725)
which is 28,000*0,9275^{5}
which equals 28,000*0.6863=$19,219
6 0
3 years ago
Which equation represents a line which is parallel to the line 2x+y=-82x+y=−8?
geniusboy [140]

Answer:

x=7 is the line parallel to the given line x=8 . Parallel lines are the lines which are always same distance apart and never intersect. The given line is x=8 with intersects the x axis at x=8 and it is parallel to y axis with slope infinite or not defined.

Step-by-step explanation:

6 0
3 years ago
In the figure below an you can see the pic plis help
Anni [7]

The measure of angle 1 and 2 should add up to 180°, because it forms a straight line. The same goes for the sum of angle 3 and 4.

Since we are given the measure of angle 2, we can find the measure of angle 1 by subtracting 143° from 180°.

180°-143° = 37°

We know that the intersecting lines form 2 sets of vertical angles, which are congruent. This means that the angles opposite from each other have the same measure. Therefore, both angle 2 & 4 have a measure of 143°, while angle 1 & 3 have a measure of 37°.

4 0
4 years ago
Write an indirect proof showing that the diagonals of a parallelogram intersect each other
____ [38]
Its an indirect proof, so 3 steps :-
1) you start with the opposite of wat u need to prove 
2) arrive at a contradiction
3) concludeReport · 29/6/2015261
since you wanto prove 'diagonals of a parallelogram bisect each other', you start wid the opposite of above statement, like below :- step1 : Since we want to prove 'diagonals of a parallelogram bisect each other', lets start by assuming the opposite, that the diagonals of parallelogram dont bisect each other.Report · 29/6/2015261


Since, we assumed that the diagonals dont bisect each other, 
OC≠OA 
OD≠OBReport · 29/6/2015261
Since, OC≠OA, △OAD is not congruent to △OCBReport · 29/6/2015261

∠AOD≅∠BOC as they are vertical angles, 
∠OAD≅∠OCB they are alternate interior angles 
AD≅BC, by definition of parallelogram 
so, by AAS, △OAD is congruent to △OCBReport · 29/6/2015261
But, thats a contradiction as we have previously established that those triangles are congruentReport · 29/6/2015261
step3 :
since we arrived at a contradiction, our assumption is wrong. so, the opposite of our assumption must be correct. so diagonals of parallelogram bisect each other.
4 0
3 years ago
Calculate the area of the shaded region between the regular polygons. Round to the nearest hundredth.
wolverine [178]

Answer:

I hope I'll help you with this but I am not sure of it all...

The area of the shaded region is 46,77

Step-by-step explanation:

To determine the area of the shaded hexagon, we must first calculate te area of the whole shaded hexagon and minus that by the white little hexagon.

The formula to calculate the area of a hexagon is (3√3 s2)/ 2

(where s = one side of the hexagon)

if one side a the little white hexagon equals 6 ft;

3√3 6ft.2/2 = 18√3/2 = 9√3

now for the bigger hexagon where one side is 12 ft;

3√3 12 ft.2/2 = 72√3/2 = 36√3

now the area of the bigger one minus the area of the smaller one;

36√3 - 9√3 = 46,77

3 0
3 years ago
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