Given
s=16t^2
where
s=distance in feet travelled (downwards) since airborne with zero vertical velocity and zero air-resistance
t=time in seconds after release
Here we're given
s=144 feet
=>
s=144=16t^2
=>
t^2=144/16=9
so
t=3
Ans. after 3 seconds, the object hits the ground 144 ft. below.
Answer: A is certainly true.
Step-by-step explanation:
Answer:
yes
Step-by-step explanation:
8 and 2/3 because each whole can be split to 3/3 :)
Answer:
18.9 or 23.625
Step-by-step explanation:
