What is the function rule

A shipping company selects 75 random packages to check their weight.It finds that 3 packages were weighed incorrectly. How many

Misha Larkins [42]

Answer: 120 Packages

Step-by-step explanation:

Given

75 random packages are check

3 package is found faulty

So, the percentage of error is

$\Rightarrow \dfrac{3}{75}\times 100=4\%$

i.e. 4% packages is faulty

For 3000 sample, expected faulty packages are

$\Rightarrow 3000\times \dfrac{4}{100}=120\ \text{Packages}$

7 0

3 years ago

SUPER SIMPLE, Please help, I will mark brainliest

insens350 [35]

Easy it is clearly A

5 0

3 years ago

Based on what you know now, how are linear and exponential functions alike?

Ainat [17]

Answer:

They're similar in that they both have to maintain a steady rate of rise as they grow. While graphing, you can't adjust the slope or exponent after traveling up a graph.

Step-by-step explanation:

5 0

3 years ago

What is two and three fifths plus one and one eighth?

goblinko [34]

2 and 3/5 + 1 and 1/8
First, find the LCM of 5 and 8: 40
Next, make equivalent fractions:
2 and 24/40 + 1 and 5/40= 3 and 29/40

Answer: 3 and 29/40

7 0

3 years ago

the height h(t) of a trianle is increasing at 2.5 cm/min, while it's area A(t) is also increasing at 4.7 cm2/min. at what rate i

nekit [7.7K]

Answer:

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Step-by-step explanation:

From Geometry we understand that area of triangle is determined by the following expression:

$A = \frac{1}{2}\cdot b\cdot h$ (Eq. 1)

Where:

$A$ - Area of the triangle, measured in square centimeters.

$b$ - Base of the triangle, measured in centimeters.

$h$ - Height of the triangle, measured in centimeters.

By Differential Calculus we deduce an expression for the rate of change of the area in time:

$\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt}$ (Eq. 2)

Where:

$\frac{dA}{dt}$ - Rate of change of area in time, measured in square centimeters per minute.

$\frac{db}{dt}$ - Rate of change of base in time, measured in centimeters per minute.

$\frac{dh}{dt}$ - Rate of change of height in time, measured in centimeters per minute.

Now we clear the rate of change of base in time within (Eq, 2):

$\frac{1}{2}\cdot\frac{db}{dt}\cdot h = \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}$

$\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt}$ (Eq. 3)

The base of the triangle can be found clearing respective variable within (Eq. 1):

$b = \frac{2\cdot A}{h}$

If we know that $A = 130\,cm^{2}$ , $h = 15\,cm$ , $\frac{dh}{dt} = 2.5\,\frac{cm}{min}$ and $\frac{dA}{dt} = 4.7\,\frac{cm^{2}}{min}$ , the rate of change of the base of the triangle in time is:

$b = \frac{2\cdot (130\,cm^{2})}{15\,cm}$

$b = 17.333\,cm$

$\frac{db}{dt} = \left(\frac{2}{15\,cm}\right)\cdot \left(4.7\,\frac{cm^{2}}{min} \right) -\left(\frac{17.333\,cm}{15\,cm} \right)\cdot \left(2.5\,\frac{cm}{min} \right)$

$\frac{db}{dt} = -2.262\,\frac{cm}{min}$

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

6 0

3 years ago