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SSSSS [86.1K]
2 years ago
6

Find the 39th term of the arithmetic sequence

Mathematics
1 answer:
myrzilka [38]2 years ago
8 0

Answer:

  -142

Step-by-step explanation:

You seem to have an arithmetic sequence with first term -66 and common difference (-68-(-66)) = -2. The general term of such a sequence is given by ...

  an = a1 +d(n -1) . . . . . for first term a1 and common difference d

We want to evaluate this equation for a1 = -66, d = -2, n = 39:

  a39 = -66 -2(39 -1) = -66 -76 = -142

The 39th term is -142.

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The segment below is dilated by a scale factor of 5 to form N'O'. What is the<br> measure of N'O'?
erma4kov [3.2K]

Answer:

N'O' = 25

Step-by-step explanation:

N'O' = 5 × NO = 5 × 5 = 25

7 0
2 years ago
A storekeeper increased the price of hats by 8% A hat was originally priced at $12.00. What is the new cost of the hat?
german

Answer:

$12.96

Step-by-step explanation:

determine what the decimal form of 8% is

⇒ 8% = 0.08

multiply $12 by 0.08

⇒ $12 x 0.08

⇒ $0.96

add $0.96 to $12

⇒ $12 + $0.96

⇒ $12.96

new price

⇒ $12.96

6 0
3 years ago
A certain bookstore chain has two stores, one in San Francisco and one in Los Angeles. It stocks three kinds of books: hardcover
riadik2000 [5.3K]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

\left[\begin{array}{cccc}T&H&S&P\\S&600&1300&2000\\L&400&300&400\end{array}\right] = A.

In the above matrix A, the columns refers the three type of books and the rows refers the from which stores the books are been sold.

The numbers represents the corresponding sales in the month of January.

The sale is same for the 6 months.

Hence, 6A = \left[\begin{array}{cccc}T&H&S&P\\S&3600&7800&12000\\L&2400&1800&2400\end{array}\right]. This matrix 6A represents the total sales over the 6 months.

(b)

If we denote the books in stock at the starting of January by B, then

B = \left[\begin{array}{cccc}T&H&S&P\\S&1000&3000&6000\\L&1000&6000&3000\end{array}\right].

Each month, the chain restocked the stores from its warehouse by shipping 500 hardcover, 1,400 softcover, and 1,400 plastic books to San Francisco and 500 hardcover, 500 softcover, and 500 plastic books to Los Angeles.

If we represent the amount restocked books at the end of each month by another matrix C, then

C = \left[\begin{array}{cccc}T&H&S&P\\S&500&1400&1400\\L&500&500&500\end{array}\right].

This restocking will be done for 5 times before the end of June.

If there would be no sale, then the stock would be

B + 5C = \left[\begin{array}{cccc}T&H&S&P\\S&1000+2500&3000+7000&6000+7000\\L&1000+2500&6000+2500&3000+2500\end{array}\right] \\= \left[\begin{array}{cccc}T&H&S&P\\S&3500&10000&13000\\L&3500&8500&5500\end{array}\right].

Since, the total sale is given by 6A, at the end of June, the inventory in each store can be shown as following,

B+5C-6A \left[\begin{array}{cccc}T&H&S&P\\S&3500&10000&13000\\L&3500&8500&5500\end{array}\right] - \left[\begin{array}{cccc}T&H&S&P\\S&3600&7800&12000\\L&2400&1800&2400\end{array}\right] \\= \left[\begin{array}{cccc}T&H&S&P\\S&-100&2200&1000\\L&1100&6700&3100\end{array}\right]

6 0
3 years ago
Help againnn. Yes, I’m kinda slow
Leni [432]

So, the right option is 1. so if my ans was helpful u can follow me.

5 0
3 years ago
WWhat is the solution to the equation 1/2 X +3 equals 2/3 X plus one
RUDIKE [14]
1/2x + 3 = 2/3x + 1....multiply everything by the common denominator of 6
3x + 18 = 4x + 6
3x - 4x = 6 - 18
-x = - 12
x = 12 <====

multiplying by the common denominator will get rid of the fractions
6 0
3 years ago
Read 2 more answers
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