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2 years ago

PLEASE HELP I WILL GIVE THE BRAINLIEST!!!!

Mathematics

2 answers:

Dafna11 [192]2 years ago

7 0

54 inch!!!!!!!!!!!!!!

AysviL [449]2 years ago

6 0

Answer:

54 in

Step-by-step explanation:

6 3/4= 27/4

27/4 x 8= 54

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A 100 mL vial of 25% solution is available in stock. An order is recieved for 6 g to be added to 250 mL of fluid for an iv infus

Ne4ueva [31]

9514 1404 393

Answer:

274 mL

Step-by-step explanation:

Often medical solutions expressed as a percentage are not really a percentage as such. A percentage is the ratio of two quantities with the same units.

Here, the context given by the problem suggests the "25%" solution is really (25 g)/(100 mL). That is, the units are grams and milliliters--different units.

With that assumption, we want to find the volume (v) of solution needed to deliver 6 g of medicine. An appropriate proportion* is ...

v/(6 g) = (100 mL)/(25 g)

v = (6 g)(100 mL)/(25 g) = 24 mL

So, the total volume of the infusion is ...

250 mL +24 mL = 274 mL

_____

* The concentration is given in terms of g/mL, but we have used a proportion that is mL/g. The reason for that is we want the variable to be in the numerator of the ratio. The variable here represents volume, so we have written the proportion with volumes in the numerators.

Having the variable in the numerator means the equation can be solved in one step--by multiplying by its denominator.

3 0

3 years ago

Given 2x – 4y= 4:<br> Transform this equation into slope-intercept form

jeka57 [31]

Answer:

y=1/2x-1

Step-by-step explanation:

-4y=4-2x

4y=4-2x

y=-1+1/2x

y=1/2x-1

8 0

3 years ago

Water is leaking out of a large barrel at a rate proportional to the square rooot of the depth of the water at that time. If the

sdas [7]

Answer:

It will take about 35.49 hours for the water to leak out of the barrel.

Step-by-step explanation:

Let $y(t)$ be the depth of water in the barrel at time $t$ , where $y$ is measured in inches and $t$ in hours.

We know that water is leaking out of a large barrel at a rate proportional to the square root of the depth of the water at that time. We then have that

$\frac{dy}{dt}=-k\sqrt{y}$

where $k$ is a constant of proportionality.

Separation of variables is a common method for solving differential equations. To solve the above differential equation you must:

Multiply by $\frac{1}{\sqrt{y}}$

$\frac{1}{\sqrt{y}}\frac{dy}{dt}=-k$

Multiply by $dt$

$\frac{1}{\sqrt{y}}\cdot dy=-k\cdot dt$

Take integral

$\int \frac{1}{\sqrt{y}}\cdot dy=\int-k\cdot dt$

Integrate

$2\sqrt{y}=-kt+C$

Isolate $y$

$y(t)=(\frac{C}{2} -\frac{k}{2}t)^2$

We know that the water level starts at 36, this means $y(0)=36$ . We use this information to find the value of $C$ .

$36=(\frac{C}{2} -\frac{k}{2}(0))^2\\C=12$

$y(t)=(\frac{12}{2} -\frac{k}{2}t)^2\\\\y(t)=(6 -\frac{k}{2}t)^2$

At t = 1, y = 34

$34=(6 -\frac{k}{2}(1))^2\\k=12-2\sqrt{34}$

So our formula for the depth of water in the barrel is

$y(t)=(6 -\frac{12-2\sqrt{34}}{2}t)^2\\\\y(t)=\left(6-\left(6-\sqrt{34}\right)t\right)^2\\$

To find the time, $t$ , at which all the water leaks out of the barrel, we solve the equation

$\left(6-\left(6-\sqrt{34}\right)t\right)^2=0\\\\t=3\left(6+\sqrt{34}\right)\approx 35.49$

Thus, it will take about 35.49 hours for the water to leak out of the barrel.

5 0

3 years ago

PLEASE HELP ASAP 30 PTS ):

ASHA 777 [7]

Answer:

Step-by-step explanation:

It's an exponential function but it is going in the negative direction. So now you know there has to be a negative in front of the function meaning it can only be c or d. Since we know its a exponential function. If we set x = 0, it will give us the y intercept. Which should be 1. However it is -2. Therefore it it multiplied by -2 meaning d is right answer

6 0

3 years ago

Read 2 more answers

3) Solve the System of Equations using Elimination/Combinations. (5 points)

Schach [20]

Answer:

(1, 2 )

Step-by-step explanation:

Given the 2 equations

- 2x - y = - 4 → (1)

x + 2y = 5 → (2)

Multiplying (2) by 2 and adding result to (1) will eliminate x- term

2x + 4y = 10 → (3)

Add (1) and (3) term by term to eliminate x

0 + 3y = 6

3y = 6 ( divide both sides by 3 )

y = 2

Substitute y = 2 into either of the 2 equations and solve for x

Substituting into (2)

x + 2(2) = 5

x + 4 = 5 ( subtract 4 from both sides )

x = 1

solution is (1, 2 )

3 0

2 years ago