Which of the following is a correct conversion factor? 1 foot = 12 cm 1 mm = 0.1 cm 1,000 kg = 1 decigram 1 ml = 10 L

How did doctors harvest and culture cells from henrietta lacks?

Assoli18 [71]

Cells were taken while she was being treated for cancer many years ago and these cells have been cultured in the lab ever since.

3 0

3 years ago

The Km of your favorite enzyme that operates by normal Michaelis-Menten kinetics is 10-6 M. You start off with a substrate conce

swat32

Answer: (a) 0 no free enzyme left

(b) 10^-9M

Explanation:

ANSWER:

Given that

Kcat = 10 sec-1

Km = 10^-6 M

[S] = 10^-3 M

[Enzyme] = 10^-9 M

The reaction follows the following path-

Enzyme (E) + Substrate (S) <=> ES complex -> E + Product (P)

According to the improved model of Michaelis-Menten kinetics, upon addition of substrate and the enzyme, instead of dynamic equilibrium, a steady state is reached. The time taken is very less, almost instantaneously (since Kcat is much higher than the concentrations we are dealing with (10 per second! Whereas we are dealing with concentrations as low as 10-9).

In this steady state, the Enzyme and substrate instead of existing individually, exist as an Enzyme-Substrate complex, or ES complex.

Physically, Km is a measure of how well substrate complexes with an enzyme, i.e. It's binding affinity.

You can imagine this as if 1 unit of the substrate can bind to "Km" units of Enzyme. For the give conditions, 1 M of the substrate requires 10^-6 M enzyme for complete binding. So, 10^-3 M of the substrate will require 10^-3 x 10^-6 = 10^-9 M of the enzyme, which is the exact amount of enzyme added to the reaction mixture.

So it is safe to assume that when the steady state is reached, all of the enzyme is bound to the available substrate producing the ES complex with the concentration equal to the limiting reactant, i.e. the enzyme = 10^-9 M

Hence, there will be no free enzyme left after the short duration of the reaction. And the concentration of the ES complex will be 10^-9 M

8 0

3 years ago

Compare a climax community to a pioneer species?

LuckyWell [14K]

<span>Climax community=when the ecosystem reaches its mature state. After every disturbance, the ecological succession will culminate in the climax community. For example, ecological succession triggered by fires in Yellowstone Park culminates in pine forests. Pioneer species are the first species to colonize an area after a disturbance occurs. They reproduce quickly and survive in harsh conditions. For example, lichens.</span>

8 0

3 years ago

•Address the letter to the editor of a local newspaper.

Julli [10]

The answer is; hydrothermal, geothermal, and wind

Hydrothermal, taped from the biggest river on the state contributes approximately 60% of the energy in the state. Geothermal is second,approximately 30% while wind power contributes approximately 10%.

The costs of the electricity in the state are relatively cheap compared with states whose main source of energy is hydrocarbon fuels. Geothermal power is the cheapest (even though initial investment is prohibitive). Hydrothermal is slightly expensive than geothermal due to the maintenance required and also is prone to fluctuations of the river regime. Winds are also cheap but initial investment if the wind farm is high.

Hydrothermal energy has the biggest environmental impact compared to the other two. Due to the walls of the dam on the river, migration of some aquatic species is impeded. The reduced flow of water (and sediments) downstream of the dam also impact these ecosystems. Geothermal and wind energy sources have a very minimal environmental impact on the environment .

The state could increase electronics with low power consumption (such as LED lights) in the market for availability to the population. This would be followed by a sensitization campaign on the ideal use of power in the household to conserve power when not in use.

4 0

2 years ago

13)

Julli [10]

Multiply 5730 years by 2 since two half-lives have gone by for carbon.

<u>Explanation</u>:

The half-life of a radioactive isotope depicts the measure of time that it takes half of the isotope in an example decay. On account of radiocarbon dating, the half-existence of carbon 14 is 5,730 years

The half-life of carbon-14 is 5730 years.

In this manner, after

1 half-life there is 50 % = 1/2 of the first amount left.

2 half-lives there is 25 % = 1/4 of the first amount left.

25% is two half-lives.

Every 50% of life requires 5730 years.

So two half-lives require 2 × 5730

6 0

3 years ago