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Elza [17]
2 years ago
9

Are the random variables Xi and Xj , where i < j, independent? Recall that two random variables X and Y are independent if P[

X = k1 ∩Y = k2] = P[X = k1]P[Y = k2] for all k1 and k2. Prove your answer using this definition.
Mathematics
1 answer:
lara31 [8.8K]2 years ago
3 0

Answer with explanation:

Consider an example of tossing a dice once

Total favorable outcome =6={1,2,3,4,5,6}

  X_{i}=\text{multiple of 2}={2,4,6}\\\\X_{j}=\text{multiple of 3}={3,6}\\\\P(\text{An Event})=\frac{\text{Total favorable outcome}}{\text{Total favorable outcome}}\\\\P(X_{i}})=\frac{3}{6}\\\\=\frac{1}{2}\\\\P(X_{j}})=\frac{2}{6}\\\\=\frac{1}{3}\\\\\rightarrow X_{i} \cap X_{j}={6}\\\\\rightarrow P(X_{i} \cap X_{j})=\frac{1}{6}\\\\\rightarrow P(X_{i} \cap X_{j})=P(X_{i})\times P(X_{j})

Hence proved.

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7 0
2 years ago
Help me please guys.
Alex_Xolod [135]
15.04 degrees or answer A is correct.


The Law of Sines is the relationship between the sides and angles of non-right (oblique) triangles . Simply, it states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is the same for all sides and angles in a given triangle. The formula for it is A=b•sin a/sin b.


You can transform the law of sines formulas to solve some problems of triangulation (solving a triangle). You can use them to find:

The remaining sides of a triangle, knowing two angles and one side.
The third side of a triangle, knowing two sides and one of the non-enclosed angles. In some cases (ambiguous cases) there may be two solutions to the same triangle. If the following conditions are fulfilled, your triangle may be an ambiguous case:
You only know the angle α and sides a and c;
Angle α is acute (α < 90°);
a is shorter than c (a < c);
a is longer than the altitude h from angle β, where h = c * sin(α) (a > c * sin(α)).

I hate useless complicated math lol ;)
5 0
3 years ago
4 bags of cement do 18m(squared), how many m(squared) can be done with 7 bags ?
Elis [28]
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4 0
3 years ago
Please help!!! Brainliest for whoever is right! What is the sum of the rational expressions below?
fenix001 [56]

Answer:

<h2>\frac{5 {x}^{2} + 5x + 3 }{3 {x}^{2}  + 3x}</h2>

Step-by-step explanation:

\frac{2x + 3}{3x}  +  \frac{x}{ x + 1}

Write all the numerators above the least common denominator

\frac{(x + 1)(2x + 3) + 3 {x}^{2} }{3x(x + 1)}

Multiply the parentheses

\frac{2 {x}^{2} + 3x + 2x + 3 + 3 {x}^{2}  }{3x(x + 1)}

Distribute 3x through the parentheses

\frac{2 {x}^{2}  + 3x + 2x + 3 + 3 {x}^{2} }{3 {x}^{2}  + 3x}

Collect like terms=\frac{5 {x}^{2} + 5x + 3 }{3 {x}^{2} + 3 x}

Hope this helps...

Good luck on your assignment...

6 0
3 years ago
Find d for the sequence for which a1 = 100 and a12 = 34.
Leviafan [203]
<span>-66 / (12 - 1) = -6 (Answer)</span>
3 0
3 years ago
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