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Ne4ueva [31]
3 years ago
12

3x^2+6x+3y^2-12y+54=0 is a ____.

Mathematics
1 answer:
alexira [117]3 years ago
8 0

Answer:

radius 2

Step-by-step explanation:


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Determine the coordinates of the vertices of the triangle to compute the area of the triangle using the distance formula (round
Karo-lina-s [1.5K]

Answer:

1. D. 50\text{ units}^2

2. D. 45 units.

Step-by-step explanation:

We have been two graphs.

1. To find the area of our given triangle we will use distance formula.

\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Upon substituting coordinates of base line of our triangle we will get,

\text{Base length of triangle}=\sqrt{(15-5)^2+(5-15)^2}  

\text{Base length of triangle}=\sqrt{(10)^2+(-10)^2}  

\text{Base length of triangle}=\sqrt{100+100}  

\text{Base length of triangle}=\sqrt{200}  

\text{Base length of triangle}=10\sqrt{2}  

Now let us find the height of triangle similarly.

\text{Height of triangle}=\sqrt{(20-15)^2+(10-5)^2}  

\text{Height of triangle}=\sqrt{(5)^2+(5)^2}  

\text{Height of triangle}=\sqrt{25+25}  

\text{Height of triangle}=\sqrt{50}  

\text{Height of triangle}=5\sqrt{2}  

\text{Area of triangle}=\frac{\text{Base*Height}}{2}

\text{Area of triangle}=\frac{10\sqrt{2}*5\sqrt{2}}{2}

\text{Area of triangle}=\frac{50*2}{2}

\text{Area of triangle}=50

Therefore, area of our given triangle is 50 square units and option D is the correct choice.

2. Using distance formula we will find the length of large side of triangle as:

\text{Large side of rectangle}=\sqrt{(14-1)^2+(21-8)^2}

\text{Large side of rectangle}=\sqrt{(13)^2+(13)^2}

\text{Large side of rectangle}=\sqrt{169+169}

\text{Large side of rectangle}=\sqrt{338}

\text{Large side of rectangle}=13\sqrt{2}

\text{Small side of rectangle}=\sqrt{(4-1)^2+(5-8)^2}

\text{Small side of rectangle}=\sqrt{(3)^2+(-3)^2}

\text{Small side of rectangle}=\sqrt{9+9}

\text{Small side of rectangle}=\sqrt{18}

\text{Small side of rectangle}=3\sqrt{2}

\text{Perimeter of rectangle}=2(\text{Length + Width)}

\text{Perimeter of rectangle}=2(13\sqrt{2}+3\sqrt{2}}

\text{Perimeter of rectangle}=2(16\sqrt{2}}

\text{Perimeter of rectangle}=32\sqrt{2}

\text{Perimeter of rectangle}=45.2548339959390416\approx 45

Therefore, the perimeter of our given rectangle is 45 units and option D is the correct choice.

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