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kotegsom [21]
2 years ago
5

Caleb borrowed $1500 from his aunt. He plans to pay his aunt back in 9 months. If he

Mathematics
1 answer:
sergeinik [125]2 years ago
4 0

Answer:

A = $1,545.00

(I = A - P = $45.00)

Equation:

A = P(1 + rt)

Explanation:

First, converting R percent to r a decimal

r = R/100 = 4%/100 = 0.04 per year.

Putting time into years for simplicity,

9 months / 12 months/year = 0.75 years.

Solving our equation:

A = 1500(1 + (0.04 × 0.75)) = 1545

A = $1,545.00

The total amount accrued, principal plus interest, from simple interest on a principal of $1,500.00 at a rate of 4% per year for 0.75 years (9 months) is $1,545.00.

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antiseptic1488 [7]

Given expression: (256x^{16})^{1/4}.

\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n

=256^{\frac{1}{4}}\left(x^{16}\right)^{\frac{1}{4}}

256=4^4

256^{\frac{1}{4}}=\left(4^4\right)^{\frac{1}{4}}=4

\left(x^{16}\right)^{\frac{1}{4}}=x^{16\cdot \frac{1}{4}}=x^4

(256x^{16})^{1/4} =4x^4

<h3>Therefore, correct option is B option : B.4x^4</h3>
6 0
3 years ago
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Bookstore sells book in excellent condition for $2.50 and in fair condition for $0.50 . Write an expression for cost of buying x
alexdok [17]
X = excellent condition books
y = fair condition books

2.50x + 0.50y <== ur expression
8 0
3 years ago
What is the slope of the function?
meriva

Answer:

I d ok not really so good luck though

4 0
2 years ago
There are 5 times as many yellow labs as terriers in the dog park .if there are a total of 18 dogs how many dogs are terriers?
tekilochka [14]
Let t = number of terriers
1 x t = number of total terriers
5 x t = number of yellow labs
1t + 5t = 6t
6t = total number of dogs in the park
6t = 18
t = 18/6
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8 0
3 years ago
A bookstore contains 75972 books,divided in to three sections. The science represents 1/3 of the total books. The remaining book
S_A_V [24]

Answer:

12,662 books

Step-by-step explanation:

Total number of books = 75,972

No. of science books = ⅓ of 75,972 = ⅓*75,972 = 25,324 books.

No. of business books = 75% of the remaining books = 75% of (75,972 - 25,324)

= \frac{75}{100}*50,648 = 37,986

No. of business books = 37,986

No. of maths books in the math section = 75,972 - (25,324 + 37,986)

= 75,972 - 63,310

= 12,662 books

7 0
3 years ago
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