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Sidana [21]
3 years ago
8

I will mark brainliest if correct

Mathematics
1 answer:
Bezzdna [24]3 years ago
4 0
51
8.5x6=51

8 1/2= 8.5
Answer: 51
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NO LINKS!! Please help me with these graphs​
Stella [2.4K]

Answer:

  • square: 9 square units
  • triangle: 24 square units

Step-by-step explanation:

Using a suitable formula the area of a polygon can be computed from the coordinates of its vertices. You want the areas of the given square and triangle.

<h3>Square</h3>

The spreadsheet in the first attachment uses a formula for the area based on the given vertices. It computes half the absolute value of the sum of products of the x-coordinate and the difference of y-coordinates of the next and previous points going around the figure.

For this figure, going to that trouble isn't needed, as a graph quickly reveals the figure to be a 3×3 square.

The area of the square is 9 square units.

<h3>Triangle</h3>

The same formula can be applied to the coordinates of the vertices of a triangle. The spreadsheet in the second attachment calculates the area of the 8×6 triangle.

The area of the triangle is 24 square units.

__

<em>Additional comment</em>

We have called the triangle an "8×6 triangle." The intention here is to note that it has a base of 8 units and a height of 6 units. Its area is half that of a rectangle with the same dimensions. These dimensions are readily observed in the graph of the vertices.

7 0
1 year ago
Find the solution of the given initial value problem. ty' + 6y = t2 − t + 1, y(1) = 1 6 , t &gt; 0
gtnhenbr [62]

Answer:

Step-by-step explanation:

Given is a differential equation as

ty' + 6y = t^2 - t + 1, y(1) = 1 6 , t > 0

Divide this by t to get in linear form

y'+6y/t = t-1+1/t

This is of the form

y' +p(t) y = Q(t)

where p(t) = 1/te^(\int 1/tdt) = t

So solution would be

yt = \int t^2-t+1 dt\\= t^3/3-t^2/2+t+C

siubstitute y(1) = 16

16 = 16^3/3-128+1+C\\C = -1206

4 0
3 years ago
The shortest distance from a point to a straight line is
Dahasolnce [82]

The shortest distance from a point to a straight line is the measurement of the line segment which connects the point to the straight line. This line segment should be perpendicular to the line and is thus called the perpendicular distance. 

5 0
3 years ago
How do you make a stem and leaf plot?
Maru [420]

Answer:

How to Make a Stem-and-Leaf Plot

Step 1: Determine the smallest and largest number in the data. The game stats: ...

Step 2: Identify the stems. For any number, the digit to the left of the right-most digit is a stem. ...

Step 3: Draw a vertical line and list the stem numbers to the left of the line.

Step 4: Fill in the leaves. ...

Step 5: Sort the leaf data.

Step-by-step explanation:

6 0
3 years ago
Solve the following eqation: 4m - 12 = 0
OLEGan [10]

Answer:

m=3

Step-by-step explanation:

Move the 12 over to the other side so it will be 4m=12, then divide each side by 4 to get m=3

8 0
2 years ago
Read 2 more answers
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