Question

Maximum value of P+4x+5y+21 given the following: y-x<1, 21x+7y<25, x>-2, y>-4

Answer 1

The maximum value of the objective function is 31.787

How to maximize the function?

The given parameters are:

Objective function:

Max P = 4x + 5y + 21

Subject to:

y- x < 1

21x + 7y < 25

x>-2,  y>-4

Rewrite the inequalities as equation

y - x = 1

21x + 7y =  25

Add x to both sides in y - x = 1

y = x + 1

Substitute y = x + 1 in 21x + 7y =  25

21x + 7x + 7 =  25

Evaluate the like terms

28x = 18

Divide both sides by 28

x = 0.643

Substitute x = 0.643 in y = x + 1

y = 0.643 + 1

y = 1.643

So, we have:

Max P = 4x + 5y + 21

This gives

P = 4 * 0.643 + 5* 1.643 + 21

Evaluate

P = 31.787

Hence, the maximum value of the objective function is 31.787

Read more about maximum functions at:

brainly.com/question/14381991

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