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sineoko [7]
3 years ago
8

Go from roots to factors, multiply the factors by FOIL technique, and write the answer in Standard Form (y=ax^2+bx+c): x=4 and x

=-2
Mathematics
1 answer:
Mama L [17]3 years ago
5 0

Answer:

(y=ax^2+bx+c): x=4 and x=-2

Step-by-step explanation:

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Mr. Johnson currently has a square garden. He wants to redesign his garden and make it into a rectangle with a length that is 5
AlekseyPX

Answer:

Width of the rectangle = 10 feet

Length of the rectangle = 25 feet

Step-by-step explanation:

Perimeter of a rectangle = 2(length + width)

Let

Width of the rectangle = x feet

Length of the rectangle = 3x - 5 feet

Perimeter of the rectangle = 70 feet

Perimeter of a rectangle = 2(length + width)

70 = 2{x + (3x - 5)}

70 = 2{x + 3x - 5}

70 = 2(4x - 5)

70 = 8x - 10

70 + 10 = 8x

80 = 8x

Divide both sides by 8

x = 80 / 8

= 10

Width of the rectangle = 10 feet

Length of the rectangle = 3(10) - 5

= 30 - 5

= 25 feet

6 0
2 years ago
How do I factorise an expression
ololo11 [35]
It factorises to -
4(x+6)

3 0
2 years ago
Please help!! Will mark brainliest
Viefleur [7K]

Answer:

21

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
if you subtract 18 from my number and multipy the difference by -3 the result is -51 what is the number
NNADVOKAT [17]

Answer:

35

Step-by-step explanation:

x-18=y

y*-3=-51

y=17

x-18=17

17+18=x

x=35

3 0
3 years ago
4. Diego is thinking of two positive numbers. He says, "If we triple the first number and
aleksandr82 [10.1K]

Answer:

3<em>x </em>+ 2<em>y</em> = 34. and two possible pairs of positive numbers are  (<em>x</em>, <em>y</em>) = (10, 2) and (<em>x</em>, <em>y</em>) = (4, 11).

Step-by-step explanation:

 Let the First positive number be <em>x</em> and second positive number be <em>y.</em>

Triple of first number = 3<em>x</em>

double of second number = 2<em>y</em>

According to question,

3<em>x </em>+ 2<em>y</em> = 34

Therefore, the equation is 3<em>x </em>+ 2<em>y</em> = 34

So the two possible pair of numbers Diego would be thinking of must satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34

Now,  3<em>x </em>+ 2<em>y</em> = 34

3<em>x </em>= 34 - 2<em>y</em>

Let x = 10 and by substituting its value in above expression,

3 \times 10 = 34 - 2y

30 = 34 - 2y

2y = 34 - 30

2y = 4

y = 2

Therefore first pair (<em>x</em>, <em>y</em>) = (10, 2)

In the same way put x = 4 then,

3<em>x </em>= 34 - 2<em>y</em>

3 \times 4 = 34 - 2y

2y = 34 - 12

2y = 22

y = 11

Therefore first pair (<em>x</em>, <em>y</em>) = (4, 11)

Therefore, (<em>x</em>, <em>y</em>) = (4, 11) and  (<em>x</em>, <em>y</em>) = (10, 2) are the two possible pairs of numbers Diego could be thinking of as these both values satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34.  

8 0
2 years ago
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