We know that
If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment. (Intersecting Secant-Tangent Theorem)
so
ST²=RT*QT
RT=7 in
QT=23+7-----> 30 in
ST²=7*30-----> 210
ST=√210-----> 14.49 in
the answer is
RT=14.49 in
The answer would be 80 because you are multiplying each number by 2. You multiply 5 x 2 = 10, 10 x 2 = 20, 20 x 2 = 40, and then 40 x 2 = 80. That is how I got the answer 80!!
Answer:
$1.50 bro
Step-by-step explanation:
If the figure does not have four congruent sides, then the shape is not a rhombus.
Answer:
The first one
Step-by-step explanation:
g(x) = ax² + bx + c
Point (0,0):
0 = a.0² + b.0 + c
c = 0
Point (2,1):
1 = a.2² + b.2 + c
4a + 2b + c = 1
But c = 0. Then:
4a + 2b = 1
Another point: (- 2, 1):
1 = a.(- 2)² + b.(- 2) + c
4a - 2b = 1
{4a + 2b = 1
{4a - 2b = 1
4a + 2b = 4a - 2b
4a - 4a = - 2b - 2b
- 4b = 0
b = 0
4a + 2b = 1
4a + 2.0 = 1
4a = 1
a = 1/4
The formula is:
g(x) = (1/4)x²
I hope I've helped you.
