Answer:
Pipe Q
Step-by-step explanation:
Two pipes p and Q fill a water tank. Each pipe fills the tank with water at a constant rate. Pipe P fills the tank with 20 gallons of water in 4 minutes. The equation in equals n = 6t shows the number of gallons of water n with which pipe Q fills the tank in t minutes. Which pipe fills the tank with more water each minute and by how much
Solution:
Pipe P fills the tank with 20 gallons of water in 4 minutes. If n represent the number of gallons of water that fills the tank in t minutes, then for pipe P:
n = 20 gallons / 4 minutes *t
n = 5t
Also, the number of gallons of water that fills the tank in t minutes for pipe Q is given by:
n = 6t
Since the rate at which pipe Q fills the tank (i.e. 6t) is greater than the rate at which pie P fills the tank (i.e. 5t), hence Pipe P fills the tank with more water each minute by 6 gallons while pipe P fills by 5 gallons each minute.
Possibly 230 minutes?? dont quote me on that lol
15-6x2=X im not sure if thats right but its what i got
Answer: d) v = 3.20 + 1.50n.
Step-by-step explanation:
Let 'v' be the price to pay in a 'n' kilometer.
Given: The price to be paid for a taxi ride includes a fixed parcel, called a flag, and a parcel that depends on the distance traveled.
Flag costs = $ 3.20 and
Each kilometre run costs = $ 1.50
Then, the amount of 'v' to pay in a 'n' kilometer race = Flag costs + (n)× (Each kilometre run costs )
⇒ v= 3.20 + 1.50n
Hence, the correct option is d) v = 3.20 + 1.50n.
Easy multiply the first number and do keep change flip
