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3 years ago

True or false the focus of an ellipse lie on the major axis of the ellipse

Mathematics

2 answers:

ladessa [460]3 years ago

8 0

Answer:

True

Step-by-step explanation:

In an ellipse, the longer axis is called the major axis and the shorter axis called the minor axis . Vertices are the endpoints of major axis and co-vertices are the endpoints of minor axis.

The midpoint of major and minor axis is known as the centre of ellipse.

Foci are the the two points on the major axis of the ellipse such that sum of distance of the foci from the point on the ellipse is constant.

Foci basically lie on the major axis.

So, the given statement ''the focus of an ellipse lie on the major axis of the ellipse'' is true.

castortr0y [4]3 years ago

5 0

Answer:

false

Step-by-step explanation:

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Plz help me with this

AnnZ [28]

Answer: $\bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}$

<u>Step-by-step explanation:</u>

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, $B=\dfrac{6}{5}$ → $P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}$

Half of that period is: $\dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}$

Calculate the period for each of the options to find a match:

$A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}$

7 0

3 years ago

There are 7 ushers and 11 technicians helping at the Harper Middle School fall play.

bearhunter [10]

Answer:

<h3>The ratio of technicians to all helpers is 11 : 7, or $\frac{11}{7}$ or 11 to 7.</h3>

Step-by-step explanation:

Given that there are 7 ushers and 11 technicians helping at the Harper Middle School fall play.
Let x be the number of ushers ( or helpers ).
Therefore x=7 helpers.
Let y be the number of technicians.
Therefore y=11 technicians.

<h3>To find the ratio of technicians to all helpers :</h3>

That is to find the ratio of y to x.

We can write the ratio of technicians to all ushers(helpers) as y : x

Which implies that 11 : 7, (since y=11 and x=7)

Or $\frac{11}{7}$ or 11 to 7

<h3>The ratio of technicians to all helpers is 11 : 7, or $\frac{11}{7}$ or 11 to 7</h3>

4 0

4 years ago

Please help I’m so confused

kari74 [83]

1) angle MIG = angle JIH

2) angle PMJ = angle QHG

3) angle MJI

4) 100

6 0

3 years ago

Two pounds of grapes cost 6$ what number belongs in the most right empty cell?

sdas [7]

Answer:

Table shown below

Step-by-step explanation:

Table shown below

To solve this problem let's use proportions.

If 2 pounds of grapes cost $6, half the amount will cost half the dollars, so the last row will have $3 in the price

For the second row, we know the price is $1, that is, one-sixth of the original given price. It should correspond to one-sixth of the amount of grapes or 2/6 pounds.

Simplifying the fraction, we get 1/3 or 0.33 pounds

6 0

3 years ago

Kay was walking along the bridge above the river. She accidentally lost her grip on her camera when she was trying to get it out

nikklg [1K]

Answer:

5 seconds it will hit the water.

Step-by-step explanation:

y=-16t²+400

add -16t² to both sides

-16t²=-400

divide both sides by 16

t²=-25

t=√25

t=5

8 0

3 years ago

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