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3 years ago

What values of x and y satisfy the system of equations {x = −2y + 1 | 13x + 8y = 11?}

Mathematics

1 answer:

Viefleur [7K]3 years ago

5 0

Y= -2/-18 or Y= 0.1111
X=-2(-0.1111)+1
or X=0.77778

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Need help pls .......

sukhopar [10]

Answer:

It should be the last one because rigid transformations doesn't change in size just where it is

7 0

3 years ago

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

Step(i):-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

Step(ii):-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

Step(iii):-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

Final answer:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

2 years ago

Simplify 4+2 squared

Tanya [424]

4+2^2
=4+(2×2)
=4+(4)
=4+4
=8

or

(4+2)^2
=(4+2) × (4+2)
=16+8+8+4
=36

hope this helps!! please make my answer brainliest to help me out, thx!!

5 0

3 years ago

Read 2 more answers

What is the domain of the following graph?

Morgarella [4.7K]

Answer:

[0,9]

Step-by-step explanation:

The domain is the first set of the ordered pair. When finding the domain you are supposed to find which x value it starts from to where it ends. The x value starts from 0 and ends and the 9th unit on the x-axis which would give us 0,9 now since both points are closed you would use these symbols [ ] to show that it is closed meaning the answer would be [0,9]

Note:

I'm sorry if this is wrong but this is what I believe the answer is.

4 0

3 years ago

Write the equation of the line that passes through the points (7, 2) and (4, -9). Put

saul85 [17]

if you were to use the first ordered pair, your answer would be y - 2 = 11/3(x-7) and with the second ordered pair : y + 9 = 11/3(x-4

5 0

2 years ago