I wonder if you mean to write
in place of
...
If you meant what you wrote, then we have


If you meant to write
(the cube root of 256), then we could go on to have
![\sqrt[3]{256}=\sqrt[3]{16^2}=\sqrt[3]{(4^2)^2}=\sqrt[3]{4^4}=\sqrt[3]{4^3\cdot4}=4\sqrt[3]4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B256%7D%3D%5Csqrt%5B3%5D%7B16%5E2%7D%3D%5Csqrt%5B3%5D%7B%284%5E2%29%5E2%7D%3D%5Csqrt%5B3%5D%7B4%5E4%7D%3D%5Csqrt%5B3%5D%7B4%5E3%5Ccdot4%7D%3D4%5Csqrt%5B3%5D4)
Answer:
A.2sinxcosx
Step-by-step explanation:
We know the trig identity
Sin (2a) = 2 sin a cos a
sin (2x) = 2 sin x cos x
Division , timetable , adding , and subtracting
With what cause I got you
Answer:
c and e
Step-by-step explanation: