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Stella [2.4K]
3 years ago
14

PLEASE HELP ME

Mathematics
1 answer:
kvasek [131]3 years ago
5 0

Answer:

28

Step-by-step explanation:

The binomial coefficient is calculated as:

nCx=\frac{n!}{x!(n-x)!}

It means that there are nCx ways to select x elements from a group of n elements.

So, If the researcher wants to determine the probability that 6 out of the next 8 individuals in his community are in favor of the president, we can replace n by 8 and x by 6 and calculated the binomial coefficient as:

8C6=\frac{8!}{6!(8-6)!}=28

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> Factor x^2 + 25 in the complex numbers.
oksian1 [2.3K]

Answer:  C) (x + 5i)(x - 5i)

<u>Step-by-step explanation:</u>

x² + 25 can be rewritten as x² - (-25)

Now use the difference of squares to factor: a² - b² = (a + b)(a - b)

√x² = x      √-25 = 5i

--> x² + 25 = (x + 5i)(x - 5i)

7 0
3 years ago
The sum of three consecutive even integers is –78. What are the integers?
Semenov [28]
You need to write 3 consecutive EVEN numbers using only one variable. multiply by 2 to ensure the numbers are even. Add or subtract  2 to get the next consecutive number.
(2x - 2) , (2x) , (2x + 2)

add them up to equal -78
-78 = (2x-2) + 2x + (2x+2)
-78 = 6x
-78/6 = x
-13 = x

the numbers are:  (2(-13)-2) , 2(-13) , (2(-13)+2) 
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6 0
3 years ago
Suppose you want to count the number of​ four-letter passwords that can be formed using the letters in the word NUMBER. The four
WITCHER [35]

Answer:

D.The password must not follow order matter

Step-by-step explanation:

We are given that suppose you want to count the number of four letters password that can be formed using the letters in the word NUMBER.

We are given that all letters in the password must be all different .There is no nothing saying about order so we can make combination without order .

We have to find the number of 4- letter password that can be formed using letters in the word NUMBER.

By using Permutation formula we find the number of 4- letters password that can be formed by using the letters N,M,B,U,E,R.

Permutation formula : The number of arrangements when taken r objects at a time out of n objects

=\frac{n!}{(n-r)!}

Total letters in word NUMBER=N,U,M,B,E,R=6

n=6,r=4

Therefore, the number of arrangements  can be made from 6 letters when 4 letters taken at a time =\frac{6!}{(6-4)!}

The number of selection can be made from 6 letters when 4 letters taken at a time =\frac{6!}{(6-4)!}

The number of selection can be made from 6 letters when 4 letters taken at a time =\frac{6\times5\times 4\times3 \times 2!}{ 2!}

n!=n(n-1)(n-2)(n-3)...........3\cdot.2\cdot.1

The number of selection can be made from 6 letters when 4 letters taken at a time =360

Option D is correct.

Answer : D.The password must not follow order matter

6 0
4 years ago
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Crazy boy [7]

Answer:

Step-by-step explanation:

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y - 0 = x + 2

y = x + 2

6 0
3 years ago
PLEASE HELP EASY 6TH GRADE MATH (pic is the possible answers) select the equation that represents the problem. let x represent t
harkovskaia [24]

Answer:

a

Step-by-step explanation:

8x=32

7 0
3 years ago
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