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Ira Lisetskai [31]
3 years ago
12

The equation of a line is 4x-3y=-4 what is the x-intercept of the line

Mathematics
1 answer:
max2010maxim [7]3 years ago
8 0
The x intercept is the point where y=0 for the equation, so plug 0 in and solve for x

4x=-4
x=-1

the intercept is at (-1,0)
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At a charity function, $150,045 was donated by three companies A, B, and C in the ratio 7 : 5 : 9. How much money did company B
Svetach [21]
35,725
this is because u can take the ratio 7+5+9=21 then take 150,045/21 which u get 7,145 then time 5 and u get 35,725
8 0
3 years ago
Read 2 more answers
Need help with intreset
stiks02 [169]

Answer:

11%/ 0.11

Step-by-step explanation:

I=prt

154=700*x*2

154=1400x

divide 1400 by both sides

=0.11

or 11%

4 0
3 years ago
Round to the nearest tenth, I will give brainlyest PLEASE
BabaBlast [244]

1. cos B= a/x

x= 11/cos 37°

x= 13.77

2. tan A= a/x

x= 4/tan 41°

x= 4.60

3. sin B = x/c

x= sin 37° × 10.3

x= 6.20

4. tan A= a/b

tan A= 4/13

A= tan-1(0.31)

A= 17°6'10"

5. cos A= b/c

cos A= 12/13

A= cos -¹(0.92)

A= 22°37'12"

6. tan B= a/b

tan B= 3/3

tan B= 1

B= tan‐¹(1)

B= 45°

7 0
2 years ago
Point M is the midpoint of segment QR. If QM = 16 + x and MR = 2(x + 2), find the length of QM.
pav-90 [236]
Just add them
QM+MR=QR
16+x+2(x+2)=QR
16+x+2x+4=QR
20+3x=QR
6 0
3 years ago
The growth of a city is described by the population functionwhereis the initial population of the city, t is the time in years,
mamaluj [8]

Complete question:

The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at

Answer:

27,800

Step-by-step explanation:

We need to obtain the initial population(P0) and constant value (k)

Population function : p(t) = P0e^kt

At t = 0, population = 19,000

19,000 = P0e^(k*0)

19,000 = P0 * e^0

19000 = P0 * 1

19000 = P0

Hence, initial population = 19,000

At t = 3; population = 23,000

23,000 = 19000e^(k*3)

23000 = 19000 * e^3k

e^3k = 23000/ 19000

e^3k = 1.2105263

Take the ln

3k = ln(1.2105263)

k = 0.1910552 / 3

k = 0.0636850

At t = 6

p(t) = P0e^kt

p(6) = 19000 * e^(0.0636850 * 6)

P(6) = 19000 * e^0.3821104

P(6) = 19000 * 1.4653739

P(6) = 27842.104

27,800 ( nearest whole number)

3 0
3 years ago
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