Since the question is incomplete, answer will be subjective. An example of Evaluating Expressions is find h + 8 − 9 j − h; where h = 7 and j = 5.
<h3>What is the Evaluating Expressions?</h3>
The evaluating expressions is known to be a form of digital and printable board work that can help students in working on substituting values in terms of variables of an algebraic expression.
Evaluating the Expression below:
h + 8 − 9 j − h;
Therefore, where h = 7 and j = 5
7+ 8 − 9 (5) − 7.
SO: 7 + 8 - 45 -7
= -37
Therefore the answer to the Evaluating Expression is -37.
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Answer:
7 1/2
Step-by-step explanation:
The length is 2 feet more than the width so L = w+2
so volume = (w+2) * w * 6
use distributive property:
(w*w + 2*w) * 6 =
(w^2+2w) *6 =
use distributive property again:
w^2 *6 + 2w*6 =
6w^2 +12w
Answer:
1
Step-by-step explanation:
21 = 3*7
65 = 5*13
CGF: to find the greatest common factor, multiply those factors both numbers have in common
GCF :1 since there are no factors in common
Step-by-step explanation:
A(t)=P(e^(rt))
Insert the values as follows:
The equation for "continual" growth (or decay) is A = Pe^(rt), where "A", is the ending amount, "P" is the beginning amount (principal, in the case of money), "r" is the growth or decay rate (expressed as a decimal), and "t" is the time (in whatever unit was used on the growth/decay rate).
34820=P(e^((.78)(5)))
34830=P(49.4024)
704.82335
Hope that helps :)
