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solniwko [45]
3 years ago
10

title="7\:+\:\left(6\:\times\:52\:+\:3\right)" alt="7\:+\:\left(6\:\times\:52\:+\:3\right)" align="absmiddle" class="latex-formula">



Thanks!
Mathematics
2 answers:
Alexxandr [17]3 years ago
8 0

Answer :

= 7 + (6 \times 52 + 3) \\ =7+(312  + 3) \\ =7 + 315 \\= 322

Snowcat [4.5K]3 years ago
6 0

= 322

Step-by-step explanation:

<h2><em>m</em><em>ultiply</em></h2>

<em>7 + (6 \times 52 + 3)</em>

<h2><em>calculate</em></h2>

<em>7 + (312 + 3)</em>

<h2><em>calculate</em><em> </em><em>again</em></h2>

<em>7 + 315</em>

<h2><em>there for the equal to the solution </em><em>is</em></h2>

<em>= 322</em>

<em>hope </em><em>it</em><em> helps</em>

<em>#</em><em>c</em><em>a</em><em>r</em><em>r</em><em>y</em><em> </em><em>on</em><em> learning</em>

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(Factorize): 10- 10-1-3​
Wittaler [7]

Answer:

=−4

Step-by-step explanation:

10−10−1−3

=0−1−3

=−1−3

=−4

7 0
2 years ago
Some fireworks are fired vertically into the air from the ground at an initial velocity of 24.5 meters per second. Find the high
krek1111 [17]

Answer:

The highest point reached by the firework is approximately 30.6 meters

Step-by-step explanation:

The upward velocity of the fireworks is given as 24.5 m/s

The equation of projectile motion for an object fired vertically upwards can be written as follows;

v² = u² - 2·g·s

Where;

v = The final velocity of the motion = 0 m/s at maximum height

u = The final velocity of the motion =  24.5 m/s

g = Acceleration due to gravity = 9.81 m/s²

s = The height reached = (The highest point reached by the firework)

By substituting the values, we have;

(0 m/s)² = (24.5 m/s)² - 2 × 9.81 m/s² × s

Which gives;

2 × 9.81 m/s² × s = (24.5 m/s)² = 600.25 m²/s²

19.62 m/s² × s = 600.25 m²/s²

s = 600.25 m²/s²/(19.62 m/s²) = 30.594 m ≈ 30.6 meters

The highest point reached by the firework is approximately 30.6 meters

3 0
3 years ago
Please Simplify 3x+2/7
otez555 [7]
Do you mean 3x+2=7
3x=7-2
3x=5
x=5 over 3
x=1.6
7 0
3 years ago
Read 2 more answers
...... trying to find domain, range rel max rel min end behavior inc intervals dec intervals. zeros..... I'm a mom trying to hel
Fiesta28 [93]

Answer:

The values are evaluated below.

Step-by-step explanation:

Given function is

-x^4-7x^3-12x^2

We have to find the domain, range, rel max, rel min, end behaviour, increasing or decreasing intervals and zeros of polynomial.

Domain:

The domain of a function is the set of all possible values of x for the given function.

Here domain is set of all real numbers R.

Range:

The range is the resulting y-values we get after substituting all the possible x-values.From the graph we see that

The range is -\infty

Relative maxima and minima of a function,  are the largest and smallest value of the function on an entire domain of function.

Relative max of -x^4-7x^3-12x^2 is 0 at x=0

and \frac{3}{512}(133\sqrt57-471) at x=\frac{-21}{8}-\frac{\sqrt57}{8}

Relative min is

\frac{-3}{512}(471+133\sqrt57) at x=\frac{-21}{8}+\frac{\sqrt57}{8}

From the graph we see that

End behaviour is  As \\x->\infty, f(x)->-\infty\\x->-\infty, f(x)->-\infty\\

Increasing intervals and decreasing intervals are

Increasing: \frac{1}{8}(\sqrt57-21)

Decreasing: \frac{1}{8}(-21-\sqrt57)  

Zeroes are :

-x^4-7x^3-12x^2=0

⇒ (-x^2)(x^2+7x+12)=0

⇒(-x^2)(x+3)(x+4)=0

Hence, zeroes are 0, 0, -3, -4



3 0
4 years ago
Read 2 more answers
Rebecca’s service charge at a beauty salon was $93.60, before tax. The sales tax rate was 8%. If she added 20% of the amount bef
Rom4ik [11]

Answer:

119.77

Step-by-step explanation:

93.60x.08=7.45 tax

93.60 x .20=18.72 tip

93.60+7.45+18.72=119.77

4 0
3 years ago
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