The vertex form is y=7(x+1)^2-3
First you have to complete the square. The first step would be 3x^2-6x=-11. Then you divide -6 by 2 and square the number you get. 3x^2-6x+9=-11+9. 3x^2-6x+9=-2. Factor out the three to get 3(x^2-2x+3)=-2. You can't factor what is in the parenthesis. You should then add two to each side. 3(x^2-2x+3)+2.A = 3B= I don't knowC = 2
Basically find the eqatuions of the lines that produce the shaded reigon
so find the lines first
we notice taht they must be inequalities
the upward line is dotted so it must have > or <
ok, hum the slope seems to be -3
the y intercept is 1 so the euaiton is y_-3x+1
the blank is the inequality
ok, test a point
(0,0) is in it
0_-3(0)+1
0_1
0<1
so it is y<-3x+1
secondn line
solid line so ≤ or ≥
slope of 2
y intercept of -1
y_2x-1
(0,0) is a possible solution
test it
0_2(0)-1
0_-1
0≥-1
so the equations are
y<-3x+1 and y≥2x-1
a. the system is y<-3x+1 and y≥2x-1
b. a solution is (0,0) because it is in the shades reigon which is the intersection of the 2 inequalities
(X-5)^2+(y-3)^2=10 is the answer
I think it could be 73. Because if you check what it the question says 73 fits them.
