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Mice21 [21]
3 years ago
15

2) An outdoor staircase has a total vertical elevation of 11 feet from the road level to the front entrance of a building. If th

e angle of elevation is 37 degrees and the landing of each step is 8 inches, answer the following questions showing each step of your work:
a) What is the vertical rise per step (in inches, rounded to the nearest whole inch)?


b) Find the number of steps needed to climb from road level to the front entrance.



3) A staircase of steps in a swimming pool has a vertical rise of 14 inches per step and a landing of 20 inches. Answer the following questions showing each step of your work:
a) What is the angle of elevation (rounded to the nearest whole degree)?


b) If the landing of each step is changed to 17 inches and the elevation of each step to 21 inches, what is the new angle of elevation for the staircase (rounded to the nearest whole degree)?


Please help me with these im confused.
Mathematics
1 answer:
LekaFEV [45]3 years ago
3 0
2a

tan37=r/8

r=8tan37

r≈6 in rise per step (to nearest whole inch)

2b

11*12/6=22 steps needed to climb the 11 ft to the entrance

...

3a

tanα=14/20

α=arctan(7/10)

α≈35° (to nearest whole degree)

..

3b

tanα=21/17

α=arctan(21/17)

α≈51° (to nearest degree)



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Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0
3 years ago
What is the inverse of y=x+5​
V125BC [204]

Answer:

x=-5

Step-by-step explanation:

4 0
3 years ago
Simplify (38 + 9 - s) + 6(4s – 32)<br>26s + 18<br>26s + 63<br>26s<br>26s - 45​
Gala2k [10]

Answer:

I don't know where those answers are coming from, but I got:

23s - 145

3 0
3 years ago
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A school has a hurdle track that is 1/5 of a mile long. They are considering extending the track to be 1/4 of a mile long. The c
Anastaziya [24]

Answer:   4/5

Step-by-step explanation:

Here,  The hurdle track that is 1/5 of a mile long.

And, After extending the track, the length of the hurdle track = 1/4 of a mile

Therefore, the unit rate of length in the longer track per mile of length in the shorter track = the initial length of the hurdle track / the final length of the hurdel track

= \frac{1/5}{1/4}

= \frac{4}{5}


3 0
3 years ago
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In 2009 there was an endangered population of 270 cranes in a western state. Due to wildlife efforts, the population is increasi
Vitek1552 [10]
Assuming compount interest format

A=P(r+1)^t for compounded per 1 year
A=future amount
P=present amount
r=rate in decimal
t=time in years


given
P=270
r=5%=0.05

the equaton is
A=270(0.05+1)^t or
A=270(1.05)^t
for any year, 2009, is year 0, so if you wanted to input the year then
A=270(1.05)^{t-2009} would be for t=what year it was

A. f(x)=270(1.05)^t


b. 2009 to 2020
2020-2009=11 years
t=11
f(11)=270(1.05)^{11}
f(11)=461.792
about 462 cranes


A. f(x)=270(1.05)^t
B. about 462
8 0
3 years ago
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