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dsp73
3 years ago
8

 In a​ company, 80​% of the workers are women. If 480 men work for the​ company, how many workers are there in​ all? Use pencil

and paper. Show two different ways that you can solve this problem. can anyone help me with this question plzz and thanks
Mathematics
1 answer:
nekit [7.7K]3 years ago
7 0

Answer:

The total workers are<u> 2400.</u>

Step-by-step explanation:

Given:

In company 80% of the workers are women.

480 workers are men.

Now, to find the total workers in all.

<u><em>In first way:</em></u>

If women are 80%, then men would be 100-80 = 20%.

Let the total workers be x.

According to question:

20\%\ of \ x=480

⇒\frac{20}{100} \times x=480

⇒0.20\times x=480

⇒0.20x=480

Dividing both sides by 0.20 we get:

⇒x=2400.

Total workers = 2400.

<em><u>Now, in second way</u></em>.

Again, let the total workers be  x.

According to question:

x-80\%\ of\ x=480

⇒x-\frac{80}{100}\times x=480

<em>On solving:</em>

⇒x-0.80x=480

⇒0.20x=480

<em>Dividing both sides by 0.20 we get:</em>

⇒x=2400.

<em>Total workers = 2400.</em>

Therefore, the total workers are <u>2400</u>.

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\large\bf{\underline{Answer:}}

\large\bf{a) \triangle  p_{1s} =  - 120 \: kgm {s}^{ - 1} }

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__________________________________________

\large\bf{\underline{In\: this\: problem\:we\:have:}}

  • \bf{N = 200\: bullets}
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❒ To find the change in momentum for bullets , we need to remember the momentum p of a bullet is equal to product of mass and speed

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❒ This means , that change in momentum for one bullet will be equal to

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\large\bf{where\:v_{f}=0}

Total change in momentum for the bullet in 10 sec is equal to product of change in momentum for one bullet and number of bullets hit the wall in 10 sec

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟼\triangle P_{10s} = N\triangle P_{i}}

<h3>❒<u> </u><u>Note </u><u>:</u><u>-</u></h3>

Change in momentum given is the change of momentum in 10 sec is 10 times less

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‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟼\triangle p_{1s}=\frac{200.(mv_{f}-mv_{i}}{10}}

\large\bf{as\:said,v_{f}=0}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟼\triangle p_{1s}=\frac{-200.mv_{i}}{10}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟼\triangle p_{1s}=\frac{200.5\times 10^{-3}kg.1200ms^{-1}}{10}}

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<h3>b) to find average force F on the wall we must remember that in general case force us the change of momentum in time :</h3>

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❒ We can find total force exerted in the wall in 10sec by dividing the momentum of bullet with 10 sec

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‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟼F = -120N}

__________________________________________

<h3>c) To find average pressure :</h3>

\large\bf{area = 3\times 10^{-4}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟼P=\frac{|F|}{A} }

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟼P=\frac{-120}{3\times 10^{-4}}}

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