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Elden [556K]
2 years ago
15

David is making cupcakes for the bake sale. He puts them on trays that hold 6 cupcakes each. How many trays will David need if h

e bakes 12 dozen cupcakes? Which equation can you use to solve the problem? One dozen is 12 cupcakes.
A.
120
÷
6
=
20
B.
144
÷
6
=
24
C.
72
÷
6
=
12
D.
96
÷
6
=
19
Mathematics
1 answer:
madreJ [45]2 years ago
6 0

Answer:

B. 144 ÷6 = 24

Step-by-step explanation:

I do not know the step by step explanation so sorry just do the answer

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A bag contains 22 coins consisting of quarters and nickels. The total value of the coins is $3.90. How many nickels are in the b
bezimeni [28]

Answer:

8 Nickels

Step-by-step explanation:

Since a Nickel is worth 5 cents ($0.05)

And a Quarter is worth 25 ($0.25)

and theres 22 coins

8 of those coins would be nickels which would mean we add 8 nickels up

8 x 0.05 = 0.4

then we add the quarters up

14 x 0.25 = 3.5

3.5 + 0.4 = $3.90

8 0
3 years ago
Calculus 2 Master needed, evaluate the indefinite integral of: <img src="https://tex.z-dn.net/?f=%5Cint%5C%28%20%28lnx%29%5E2%7D
viva [34]

Answer:

\int (\ln(x))^2dx=x(\ln(x)^2-2\ln(x)+2)+C

Step-by-step explanation:

So we have the indefinite integral:

\int (\ln(x))^2dx

This is the same thing as:

=\int 1\cdot (\ln(x))^2dx

So, let's do integration by parts.

Let u be (ln(x))². And let dv be (1)dx. Therefore:

u=(\ln(x))^2\\\text{Find du. Use the chain rule.}\\\frac{du}{dx}=2(\ln(x))\cdot\frac{1}{x}

Simplify:

du=\frac{2\ln(x)}{x}dx

And:

dv=(1)dx\\v=x

Therefore:

\int (\ln(x))^2dx=x\ln(x)^2-\int(x)(\frac{2\ln(x)}{x})dx

The x cancel:

=x\ln(x)^2-\int2\ln(x)dx

Move the 2 to the front:

=x\ln(x)^2-2\int\ln(x)dx

(I'm not exactly sure how you got what you got. Perhaps you differentiated incorrectly?)

Now, let's use integrations by parts again for the integral. Similarly, let's put a 1 in front:

=x\ln(x)^2-2\int 1\cdot\ln(x)dx

Let u be ln(x) and let dv be (1)dx. Thus:

u=\ln(x)\\du=\frac{1}{x}dx

And:

dv=(1)dx\\v=x

So:

=x\ln(x)^2-2(x\ln(x)-\int (x)\frac{1}{x}dx)

Simplify the integral:

=x\ln(x)^2-2(x\ln(x)-\int (1)dx)

Evaluate:

=x\ln(x)^2-2(x\ln(x)-x)

Now, we just have to simplify :)

Distribute the -2:

=x\ln(x)^2-2x\ln(x)+2x

And if preferred, we can factor out a x:

=x(\ln(x)^2-2\ln(x)+2)

And, of course, don't forget about the constant of integration!

=x(\ln(x)^2-2\ln(x)+2)+C

And we are done :)

8 0
3 years ago
The first person who answers correctly gets thanks and braniy!
Nuetrik [128]
That arrow helps a lot.
One
Scale factor = 21/14 = (3*7)/(2*7) = 3/2 the sevens cancel out.

Two
Scale factor = 24/18 = (6 *4) / (6 * 3) The 6s cancel out 
Scale factor = 4/3
8 0
3 years ago
Bacon Cinnamon<br> Under 13 years old<br> 4<br> 7<br> A teenager<br> 4<br> 3
Akimi4 [234]

Answer:

ok lol i guess

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Please help me for brainliest.
Kamila [148]

Answer:

Step-by-step explanation:

D

3 0
2 years ago
Read 2 more answers
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