The sum of three consecutive odd numbers is 63. What is the smallest of these numbers?
2 answers:
Answer: The smallest number = 19
Step-by-step explanation:
We'll call X the smallest of those odd numbers
Then x + (x+2) + (x+4) = 63
X + X + 2 + X + 4 = 63
3X + 6 = 63
3X = 63 - 6 = 57
X = 57/3 = 19
The three consecutives odd numbers are 19, 21, 23
The sum = 19+21+23 = 63
Your answer : The smallest number = 19
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Answer:
The correct option is `(y −4) = -(4)/(3) (x +3) ..
Step-by-step explanation:
Look at the attached picture:
The points we have given are (-3, 4) and (3, -4)
Find the slope by applying the formula:
m = y2-y1/x2-x1
Here x1= -3
x2= 3
y1 = 4
y2 = -4
Now put the values in the formula:
m = -4 -4 /3 -(-3)
m = -8/3+3
m = -8/6
Now cancel the term by table of 2
m = -4/3
When two points are given, the equation of the line is
(y - y1) = m (x - x1)
y - 4 = -4/3 (x - (-3))
y-4 = -4/3 (x+3)
Thus the correct option is `(y −4) = -(4)/(3) (x +3) ....
