Question

The sum of three consecutive odd numbers is 63. What is the smallest of these numbers?

Answer 1

Answer: The smallest number = 19

Step-by-step explanation:

We'll call X the smallest of those odd numbers

Then x + (x+2) + (x+4) = 63

X + X + 2 + X + 4 = 63

3X + 6 = 63

3X = 63 - 6 = 57

X = 57/3 = 19

The three consecutives odd numbers are 19, 21, 23

The sum = 19+21+23 = 63

Your answer : The smallest number = 19

$\textit{\textbf{Spymore}}$​​​​​​

Answer 2

x+x+2+x+4=63

3x+6=63

3x=57

x= 19 smallest number