The sum of three consecutive odd numbers is 63. What is the smallest of these numbers?
2 answers:
Answer: The smallest number = 19
Step-by-step explanation:
We'll call X the smallest of those odd numbers
Then x + (x+2) + (x+4) = 63
X + X + 2 + X + 4 = 63
3X + 6 = 63
3X = 63 - 6 = 57
X = 57/3 = 19
The three consecutives odd numbers are 19, 21, 23
The sum = 19+21+23 = 63
Your answer : The smallest number = 19
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Answer:
Train A's unit rate is 67 km per hour.
Train B's unit rate is 75 km per hour.
Train B is faster than Train A
Step-by-step explanation:
Train A
Distance traveled by Train A is represented by :
where represents distance traveled in kilometers and
is the time in hours.
To find the unit rate of Train A, we will plugin and get the distance traveled by Train A in 1 hour which will be the unit rate of Train A in km/hr.
So, distance traveled by Train A in 1 hour = 67 km
∴ Train A's unit rate is 67 km per hour.
Train B
For Train B, we are given the table for the time in hours and distance traveled in that duration.
Taking time =2 hours the distance traveled by Train B= 75 km
To find distance traveled in 1 hour we apply unitary method.
So
So, distance traveled by Train B in 1 hour = 75 km
∴ Train B's unit rate is 75 km per hour.
Difference in units rates =
On comparing their unit rate i.e. the speed of the trains we find out that Train B is faster than Train A by 8 km/hr