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3 years ago

Please show your work for brainliest!!

Mathematics

1 answer:

Digiron [165]3 years ago

5 0

Answer:

About 11.299 hours.

Step-by-step explanation:

To solve this problem, you can set up an equation to model the decay of the medicine. Let's call the time that medicine has been in the body x.

$(1-0.0595)^x=0.5$

$0.9405^x=0.5$

Taking the log x of both sides, you get

$x=\log_{0.9405} 0.5$

$x\approx 11.299$ hours. Hope this helps!

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emily bought 3 vases of flowers.the most expensive vase of flowers was 12.00 and least expensive was 8.00 which is a reasonable

iogann1982 [59]

Answer:$30

Step-by-step explanation:8+12=20 and I would figure she had another one with a price inbetween the two so I chose 10 and added 20+10=30

4 0

3 years ago

Find the number of elements in A 1 ∪ A 2 ∪ A 3 if there are 200 elements in A 1 , 1000 in A 2 , and 5, 000 in A 3 if (a) A 1 ⊆ A

lina2011 [118]

Answer:

a. 4600

b. 6200

c. 6193

Step-by-step explanation:

Let $n(A)$ the number of elements in A.

Remember, the number of elements in $A_1 \cup A_2 \cup A_3$ satisfies

$n(A_1 \cup A_2 \cup A_3)=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)$

Then,

a) If $A_1\subseteq A_2, n(A_1 \cap A_2)=n(A_1)=200$ , and if $A_2\subseteq A_3, n(A_2\cap A_3)=n(A_2)=1000$

Since $A_1\subseteq A_2\; and \; A_2\subseteq A_3, \; then \; A_1\cap A_2 \cap A_3= A_1$

$n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-200-200-1000-200=4600$

b) Since the sets are pairwise disjoint

$n(A_1 \cup A_2 \cup A_3)=\\n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\200+1000+5000-0-0-0-0=6200$

c) Since there are two elements in common to each pair of sets and one element in all three sets, then

$n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-2-2-2-1=6193$

8 0

2 years ago

A freight trains departs from one train station to its destination at a constant speed. Suppose the distance the train is from t

marysya [2.9K]

Answer:

Distance = 54 miles (Approx)

Step-by-step explanation:

Given:

Co-ordinate of two point = (0.5,135) and (2,81)

Find:

Distance

Computation:

Distance = √(x1-x2)²+(y1-y2)²

Distance = √(2-0.5)²+(81-135)²

Distance = √2.25 + 2916

Distance = 54 miles (Approx)

6 0

3 years ago

How do you work the problem 6752-3827 to get the answer

Anestetic [448]

Answer:

you subtract and get 2925

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

#31 please help and show work thank you in advance

antiseptic1488 [7]

The base price of the car is about $22,196 because:

x= major options package

10x + x = 24,416

*the 10x is the price of the car

This then simplifies to

11x = 24,416

use division.

The destination charge is not needed unless you want to check your answer. If you have to then you would do the same thing. The equation would be:

y= destination charge

5y + y = 24,416

Hope this helps.

6 0

2 years ago