Complete Question
Suppose there was a cancer diagnostic test was 95% accurate both on those that do and 90% on those do not have the disease. If 0.4% of the population have cancer, compute the probability that a particular individual has cancer, given that the test indicates he or she has cancer.
Answer:
The probability is 
Step-by-step explanation:
From the question we are told that
The probability that the test was accurate given that the person has cancer is

The probability that the test was accurate given that the person do not have cancer is

The probability that a person has cancer is

Generally the probability that a person do not have cancer is

=> 
=> 
Generally the probability that a particular individual has cancer, given that the test indicates he or she has cancer is according to Bayes's theorem evaluated as

=> 
=> 
The answer to the question is A.) 42
They are not
It goes from
0/0 1/3 2/5 3/6(or 1/2) which are not the same. This makes them not proportional to one another. (I think)
The answer is 114.5%.
Let the original population be denoted by x.
Now, let's go through the percentage increase per year.
<u>Year 1</u>
<u>Year 2</u>
- 1.2x (1 + 25%)
- 1.2x (1.25)
- 1.5x
<u>Year 3</u>
- 1.5x (1 + 30%)
- 1.5x (1.3)
- 1.95x
<u>Year 4</u>
- 1.95x (1 + 10%)
- 1.95x (1.1)
- 2.145x
Overall increase : 214.5% - 100% = 114.5%
Hence, the overall percentage increase in these 4 years is 114.5%.