Multiply 2.25 by each answer and 750 and write down the total next multiply 3.25 by each answer lowest to highest once you get a product that is higher than you writen down answer play around with the numbers until you get the exact amount D 760 2.25 times 760 is 2460 by 3.25 its 2570 you save 10 dalloars and are able to pay for the food and band
Answer:
12
Step-by-step explanation:
12 + 15 = 27
15 - 12 = 3
therefore the answers should be 12 becuase 12 is smaller than 15
Answer:
the number of seconds that you and your friend would be have the similar distance from the starting line is 20 seconds
Step-by-step explanation:
The computation of the number of seconds that you and your friend would be have the similar distance from the starting line is shown below:
As we know that
Speed = Distance ÷ Time
SO,
Time = Distance ÷ speed
= 10 meters ÷ difference in speed
= 10 meters ÷ (6 meters per second - 5.5 meters per second)
= 10 meters ÷ 0.5 meters per second
= 20 seconds
hence, the number of seconds that you and your friend would be have the similar distance from the starting line is 20 seconds
Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
